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Mariulka [41]
2 years ago
13

The area of the triangle is square inches. fill in the blanks

Mathematics
1 answer:
Dvinal [7]2 years ago
3 0

Answer:

48sq^2

Step-by-step explanation:

(12*8)/2

96/2

48

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-3(2z - 8d)<br> use z = 6 and d = 7
Ad libitum [116K]

Answer:

132

Step-by-step explanation:

1. -3(2z-8d) Solve within the parenthesis.

2. 2(6)=12, 8(7)=56

3. Do the math within the parenthesis with our new integers. 12-56=-44

4. multiply both integers now. -3(-44) = 132

*a negative times a negative wil give you a positive answer.

4 0
3 years ago
Read 2 more answers
Solve x TN = 8 nV =x - 2?
AleksandrR [38]

Answer:

10

Step-by-step explanation:

STUV is a parallelogram.

TV and SU are its diagonals intersecting at point N.

Diagonals of a parallelogram bisects each other.

Therefore, TN = NV

8 = x - 2

8 + 2 = x

10 = x

x = 10

7 0
3 years ago
True or false. the points on a line can be paired one to one with real mumbers
frosja888 [35]
This is true, because there is an infinite amount of real numbers in both, and they are both countably infinite (so these infinities are equal). Hope this helps!
3 0
3 years ago
Read 2 more answers
For a given IQ test, an individual is considered a genius if their score falls more than three standard deviations from the mean
ki77a [65]

Answer:

P(Z>3) = 1-P(Z

So then the probability that an individual present and IQ higher than 3 deviation from the mean is 0.00135

And if we find the number of individuals that can be considered as genius we got: 0.00135*1500=2.025

And we can say that the answer is a.2

Step-by-step explanation:

1) Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".  

2) Solution to the problem

Let X the random variable that represent the IQ scores of a population, and for this case we know the distribution for X is given by:

X \sim N(\mu=?,\sigma=?)  

We are interested on this probability

P(X>X+3\mu)

And the best way to solve this problem is using the normal standard distribution and the z score given by:

z=\frac{x-\mu}{\sigma}

And we can find the following probablity:

P(Z>3) = 1-P(Z

So then the probability that an individual present and IQ higher than 3 deviation from the mean is 0.00135

And if we find the number of individuals that can be considered as genius we got: 0.00135*1500=2.025

And we can say that the answer is a/2.0

3 0
3 years ago
HELP QUICK PLEASE!!!
exis [7]

Answer:

100

Step-by-step explanation:

7 0
3 years ago
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