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3 years ago

60 POINTS 60 POINTS 60 POINTS 60 POINTS Please give the correct answers

Mathematics

2 answers:

tester [92]3 years ago

3 0

<h3>Answer:</h3>

Ratio of perimeters for two pentagons are:

32cm²/98cm²
16/49 (Divided by 2)

Correct choice - [A] 16:49.

Monica [59]3 years ago

3 0

$\boxed{\large{\bold{\blue{ANSWER~:) }}}}$

The ratio of perimeters for two regular Pentagon

ones is =32cm^2
another =98cm^2

we have to find the ratio.

$\sf{ Ratio=\dfrac{1st~one}{second one} }$

$\sf{ratio=\dfrac{32}{98} }$

$\sf{ratio=\dfrac{16}{ 49} }$

$\sf{ratio =16:49 }$

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The question is an illustration of related rates.

The rate of change between you and the ball is 0.01 rad per second

I added an attachment to illustrate the given parameters.

The representations on the attachment are:

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$\mathbf{\theta = \frac{\pi}{4}}$

First, we calculate the vertical distance (y) using tangent ratio

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Substitute values for the rates and $\mathbf{\theta }$

$\mathbf{ \sec^2(\pi/4) \cdot \frac{d\theta}{dt} = \frac{1}{100} \cdot 2}$

This gives

$\mathbf{ (\sqrt 2)^2 \cdot \frac{d\theta}{dt} = \frac{1}{100} \cdot 2}$

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Divide both sides by 2

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