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Alik [6]
3 years ago
10

What is the magnitude of the electric field strength between them, if the potential 7.05 cm from the zero volt plate (and 2.95 c

m from the other) is 293 V?
Physics
1 answer:
posledela3 years ago
6 0

Answer:

E = 4156.02 Vm⁻¹

Explanation:

The magnitude of the uniform electric field between the plates can be given by the following formula:

E = \frac{\Delta V}{d}\\

where,

E = Electric field strength = ?

ΔV = Potetial Difference = 293 V

d = distance between plates = 7.05 cm = 0.0705 m

Therefore,

E = \frac{293\ V}{0.0705\ m}\\\\

<u>E = 4156.02 Vm⁻¹</u>

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Choose the three statements that are true about valence electrons.
Varvara68 [4.7K]

We have that valence electrons poses the three characteristics stated, as

Group 14 (carbon group)  are identified by 4 valence electrons.

Valence electrons of atoms are used to form bonds.

Group 14 (carbon group)  are identified by 4 valence electrons.

Option A,B,C

<h3>Properties of Valence electrons</h3>

All elements in the same group or family have the same number of valence electrons: Yes, this is true as Group 14 (carbon group) are identified by 4 valence electrons.

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6 0
3 years ago
A jet can travel the 6000 km distance between washington,
Andrei [34K]
<span> d = r*t is the basic distance equation
 d = 6000 km
 t with the tail wind = 6 hr
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An object is thrown upward from the top of a 144​-foot building with an initial velocity of 128 feet per second. The height h of
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Answer:

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Step-by-step explanation:

We equation of motion given as h = -16t²+128t+144,

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Negative time is not possible, hence after 9 seconds the object reaches ground.

8 0
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