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Alik [6]
3 years ago
10

What is the magnitude of the electric field strength between them, if the potential 7.05 cm from the zero volt plate (and 2.95 c

m from the other) is 293 V?
Physics
1 answer:
posledela3 years ago
6 0

Answer:

E = 4156.02 Vm⁻¹

Explanation:

The magnitude of the uniform electric field between the plates can be given by the following formula:

E = \frac{\Delta V}{d}\\

where,

E = Electric field strength = ?

ΔV = Potetial Difference = 293 V

d = distance between plates = 7.05 cm = 0.0705 m

Therefore,

E = \frac{293\ V}{0.0705\ m}\\\\

<u>E = 4156.02 Vm⁻¹</u>

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3 years ago
A certain first-order reaction is 58% complete in 95 s. What are the values of the rate constant and the half-life for this proc
guajiro [1.7K]

Answer:

0.005734 s^{-1} and 20.86 seconds are the values of the rate constant and the half-life for this process respectively..

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Expression for rate law for first order kinetics is given by:

a_o=a\times e^{-kt}

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k = rate constant  

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3 0
3 years ago
A shot is fired at an angle of 60 degree horizontal with Kinetic energy E. If air resistance is ignored, the K.E at the top of t
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I'm not sure what "60 degree horizontal" means.

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That much of its KE gets used up by climbing against gravity.

-- 0.25 of its kinetic energy is due to its horizontal velocity.
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