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Alik [6]
3 years ago
10

What is the magnitude of the electric field strength between them, if the potential 7.05 cm from the zero volt plate (and 2.95 c

m from the other) is 293 V?
Physics
1 answer:
posledela3 years ago
6 0

Answer:

E = 4156.02 Vm⁻¹

Explanation:

The magnitude of the uniform electric field between the plates can be given by the following formula:

E = \frac{\Delta V}{d}\\

where,

E = Electric field strength = ?

ΔV = Potetial Difference = 293 V

d = distance between plates = 7.05 cm = 0.0705 m

Therefore,

E = \frac{293\ V}{0.0705\ m}\\\\

<u>E = 4156.02 Vm⁻¹</u>

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