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3 years ago

Choose the three statements that are true about valence electrons.

Physics

1 answer:

Varvara68 [4.7K]3 years ago

6 0

We have that valence electrons poses the three characteristics stated, as

Group 14 (carbon group) are identified by 4 valence electrons.

Valence electrons of atoms are used to form bonds.

Group 14 (carbon group) are identified by 4 valence electrons.

Option A,B,C

<h3>Properties of Valence electrons</h3>

All elements in the same group or family have the same number of valence electrons: Yes, this is true as Group 14 (carbon group) are identified by 4 valence electrons.

Valence electrons are the only subatomic particles involved in forming bonds: Yes, Valence electrons of atoms are used to form bonds.

Carbon has 4 valence electrons because it is found in group 14:

True, Group 14 (carbon group) are identified by 4 valence electrons.

For more information on atoms visit

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3 years ago

Two cylindrical rods, one copper and the other iron, are identical in lengths and cross-sectional areas. They are joined, end to

Pie

Answer:

Vc = 2.41 v

Explanation:

voltage (v) = 16 v

find the voltage between the ends of the copper rods .

applying the voltage divider theorem

Vc = V x ( $\frac{Rc}{Rc + Ri}$ )

where

Rc = resistance of copper = $\frac{ρl}{a}$ (l = length , a = area, ρ = resistivity of copper)

Ri = resistance of iron = $\frac{ρ₀l}{a}$ (l = length , a = area, ρ₀ = resistivity of copper)

Vc = V x ( $\frac{\frac{ρl}{a}}{\frac{ρl}{a} + \frac{ρ₀l}{a}}$ )

Vc = V x ( $\frac{ρ x (\frac{l}{a})}{(ρ + ρ₀) x (\frac{l}{a})}$ )

Vc = V x ( $\frac{ρ}{ρ + ρ₀}$ )

where

ρ = resistivity of copper = 1.72 x 10^{-8} ohm.meter

ρ₀ = resistivity of iron = 9.71 x 10^{-8} ohm.meter

Vc = 16 x ( $\frac{1.72 x 10^{-8}}{1.72 x 10^{-8} + 9.71 x 10^{-8}}$ )

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3 years ago

Are Carbon and oxygen are both metalloids?

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3 years ago

Astronauts on the first trip to Mars take along a pendulumthat has a period on earth of 1.50 {\rm s}. The period on Mars turns o

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Answer:

3.7 m/s^2

Explanation:

The period of a simple pendulum is given by:

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where L is the length of the pendulum and g is the free-fall acceleration on the planet.

Calling L the length of the pendulum, we know that:

$T_e = 2 \pi \sqrt{\frac{L}{g_e}}=1.50 s$ is the period of the pendulum on Earth, and $g_e = 9.8 m/s^2$ is the free-fall acceleration on Earth

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Dividing the two expressions we get

$\frac{T_e}{T_m}=\sqrt{\frac{g_m}{g_e}}$

And re-arranging it we can find the value of the free-fall acceleration on Mars:

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3 years ago