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Sophie [7]
3 years ago
5

What is a real life example of something impermeable? (please help now!!) (due tomorrow!!)

Physics
1 answer:
Nutka1998 [239]3 years ago
6 0
Impermeable is a substance that is water proofed e.g glass, aluminium e.t.c <span />
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angela uses a force of 25 newtons to lift her grocery bag while doing 50 joules of work. how far did she lift the grocery bags
Evgen [1.6K]
We know that:
W=Fs
50J=25N*s
s=50J/25N
s=2m
5 0
3 years ago
A car accelerates at a rate of 3 m/s^2. If it's original speed is 8 m/s, how many seconds will it take the car to reach a final
Ksivusya [100]
26-8/3 = 6 seconds
to do it
8 0
3 years ago
An accepted value for the acceleration due to gravity is 9.801 m/s2. In an experiment with pendulums, you calculate that the val
Fed [463]

g Generally the accepted value of acceleration due to gravity is 9.801 m/s^2

as per the question the acceleration due to gravity is found to be 9.42m/s^2 in an experiment performed.

the difference between the ideal and observed value is 0.381.

hence the error is -\frac{0.381}{9.801} *100

                                                            =3.88735 percent

the error is not so high,so it can be  accepted.

now we have to know why this occurs-the equation of time period of the simple pendulum is give as-T=2\pi\sqrt[2]{l/g}

                                                      g=4\pi^2\frac{l}{T^2}

As the experiment is done under air resistance,so it will affect to the time period.hence the time period will be more which in turn decreases the value of g.

if this experiment is done in a environment of zero air resistance,we will get the value of g which must be approximately equal to 9.801  m/s^2

5 0
3 years ago
Let x define the position of an object such that x =
timama [110]
See the attached picture for answers

7 0
2 years ago
What potential increase vac must an electron be accelerated through if the most energetic photon it can emit will scatter off of
nikitadnepr [17]
Referring to Compton scattering 
Δλ = h/m₀c (I- cos Ф)
λ' =λ = (0,0242×10⁻¹⁰) (1- cos 60°)
λ= λ' -(0.0242 × 10⁻¹⁰) (1- cos 60°)

7.19 ˣ 10⁻¹²m

The increased potential is given by 
Vₐc = hc/eλ = 6.625 × 10 ⁻³⁴ J,s) ( 3× 10⁸ m/s ( 1.6 ˣ 10 ⁻¹⁰C)
(7.19 ˣ 10⁻¹²m)

173kV.
7 0
2 years ago
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