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posledela
3 years ago
11

The image of a distant tree is virtual and very small when viewed in a curved mirror. The image appears to be 22.9 cm behind the

mirror. What kind of mirror is it?
What is its radius of curvature? (in cm)
Physics
2 answers:
lord [1]3 years ago
7 0

Answer:

45.8 cm

Explanation:

distance of object from the mirror is infinity

distance of image, v = 22.9 cm

The mirror is convex because it is used to see the distant objects and the image formed by the mirror is erect and small.

use mirror formula

Let f be the focal length of the mirror

1 / f = 1 / v + 1 / u

1 / f = 1 / 22.9  + 1 / ∞

f = 22.9 cm

radius of curvature = 2 x focal length

radius of curvature = 2 x 22.9 = 45.8 cm

Dovator [93]3 years ago
4 0

Answer:

<em>A. The mirror is a convex mirror</em>

<em>B.  The radius of curvature of the convex mirror is -45.8 cm</em>

Explanation:

A. Obtaining the focal length

The radius of curvature is twice the size of the focal length, the focal length is related to object and image distance with the expression below;

1 / f = 1 / v + 1 / u ...................1

f is the focal length

Since the image (v) is formed at the back of the mirror v = -22.9 cm

u is the distance of the object from the mirror  =  ∞

Substituting into equation 1

1 / f = 1 / [(-22.9)  + 1 / ∞]

1/f = 1/(-22.9)

f = -22.9

Since the focal length is negative, the mirror is  convex.

B The radius of curvature

The radius of curvature is twice the focal length of the mirror and expressed  thus;

radius of curvature = 2 x focal length

r = 2 x f

r = 2 x (-22.9 cm)

 = -45.8 cm

Therefore the radius of curvature of the convex mirror is -45.8 cm

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galina1969 [7]

Answer:

False

Explanation:

ac = v^2/r

acceleration is not dependent on the mass of the orbiting object.

3 0
2 years ago
A rabbit is moving in the positive x-direction at 1.10 m/s when it spots a predator and accelerates to a velocity of 10.9 m/s al
anzhelika [568]

Answer:

aₓ = 0 ,       ay = -6.8125 m / s²

Explanation:

This is an exercise that we can solve with kinematics equations.

Initially the rabbit moves on the x axis with a speed of 1.10 m / s and after seeing the predator acceleration on the y axis, therefore its speed on the x axis remains constant.

x axis

          vₓ = v₀ₓ = 1.10 m / s

          aₓ = 0

y axis

initially it has no speed, so v₀_y = 0 and when I see the predator it accelerates, until it reaches the speed of 10.6 m / s in a time of t = 1.60 s. let's calculate the acceleration

         v_{y}= v_{oy} -ay t

          ay = (v_{oy} -v_{y}) / t

          ay = (0 -10.9) / 1.6

          ay = -6.8125 m / s²

the sign indicates that the acceleration goes in the negative direction of the y axis

8 0
3 years ago
What type of energy waves are used in Solar Cells, and what is it’s position on the electromagnetic spectrum?
Artyom0805 [142]

Answer: Electromagnetic waves (Ultraviolet light, between 100 nm and 380 nm)

Explanation:

Solar cells work by the photoelectric effect, which consists of the emission of electrons (electric current) when light (electromagnetic waves) falls on a metal surface under certain conditions.  

In this sense, the portion of the electromagnetic spectrum this cells use is Ultraviolet light (UV) from the Sun, whose wavelength is approximately between 100 nm and 380 nm.

It is important to note, this is a type of electromagnetic radiation that is not visible to the human eye.

3 0
3 years ago
A type of light bulb is labeled having an average lifetime of 1000 hours. It’s reasonable to model the probability of failure of
SashulF [63]

Answer:

0.2592 \ or \ 25.92\%

Explanation:

The exponential density function is given as

f(t)=\left \{ {{0} \atop {ce^{ct}}} \right\\0,t

\mu=\frac{1}{c}\\c=\frac{1}{\mu}\\\\=\frac{1}{1000}=0.001\\\\f(t)=0.001e^{-0.001t}

To find probability that bulb fails with the first 300hrs, we integrate from o to 300:

P(0\leq X\leq 300)=\int\limits^{300}_0 {f(t)} \, dt\\\\=\int\limits^{300}_0 {0.001e^{-001t}} \, dt\\ =|-e^{-0.001t}|  \ 0\leq t\leq 300

P(0\leq X\leq 300)=-0.7408+1\\=0.2592

Hence probability of bulb failing within 300hrs is 25.92% or 0.2592

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