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MrRissso [65]
3 years ago
7

what is the resistance of a 12m long wire having radius( 2*10 to the power - 4) and resistivity (3.14*10 to the power - 8)ohmM

Physics
1 answer:
Arisa [49]3 years ago
3 0
R = ρl/A

Where R = Resistance in Ohms, Ω, ρ = Resistivity in Ωm, l = Length in m.

Area in m²

ρ = Resistivity = 3.14 * 10⁻⁸ Ωm,  Length l = 12m, 

Area = πr² = π* (2*10⁻⁴)² m² ≈ 3.14 * (2*10⁻⁴)² m²


R = ρl/A

    ≈ 3.14 * 10⁻⁸ * 12 / (3.14 * (2*10⁻⁴)²)

     ≈ 3

Resistance, R ≈ 3 Ω
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La respuesta sería 200Hz

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3 years ago
This is a problem about a child pushing a stack of two blocks along a horizontal floor. The masses of the blocks, and the coeffi
Rufina [12.5K]

Answer:

 N = 23.4 N

Explanation:

After reading that long sentence, let's solve the question

The contact force is the so-called normal in this case we can find it by writing the translational equilibrium equation for the y axis

            N - w₁ -w₂ =

            N = m₁ g + m₂ g

            N = g (m₁ + m₂)

let's calculate

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7 0
3 years ago
What is the magnitude of the sum of the two vectors A = 36 units at 53 degrees, and B =47 units at 157 degrees.
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Answer:

51.82

Explanation:

First of all, let's convert both vectors to cartesian coordinates:

Va = 36 < 53° = (36*cos(53), 36*sin(53))

Va = (21.67, 28.75)

Vb = 47 < 157° = (47*cos(157), 47*sin(157))

Vb = (-43.26, 18.36)

The sum of both vectors will be:

Va+Vb = (-21.59, 47.11)   Now we will calculate the module of this vector:

|Va+Vb| = \sqrt{(-21.59)^2+(47.11)^2}=51.82

4 0
4 years ago
1. What is the kinetic energy of a 1.75 kg ball travelling at a speed of 54 m/s?
Over [174]

Answer:

We conclude that the kinetic energy of a 1.75 kg ball traveling at a speed of 54 m/s is 2551.5 J.

Explanation:

Given

  • Mass m = 1.75 kg
  • Velocity v = 54 m/s

To determine

Kinetic Energy (K.E) = ?

We know that a body can possess energy due to its movement — Kinetic Energy.

Kinetic Energy (K.E) can be determined using the formula

K.E=\frac{1}{2}mv^2

where

  • m is the mass (kg)
  • v is the velocity (m/s)
  • K.E is the Kinetic Energy (J)

now substituting m = 1.75, and v = 54 in the formula

K.E=\frac{1}{2}mv^2

K.E=\frac{1}{2}\left(1.75\right)\left(54\right)^2

K.E=1458\times 1.75

K.E=2551.5 J

Therefore, the kinetic energy of a 1.75 kg ball traveling at a speed of 54 m/s is 2551.5 J.

7 0
3 years ago
When energy is changed from one form to another, ____.
vampirchik [111]
I think b is the answer but im not 100% sure
5 0
4 years ago
Read 2 more answers
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