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steposvetlana [31]
3 years ago
8

rmula1" title="4 \times 8 ^{2x + 1?} = 32 ^{x + 2} " alt="4 \times 8 ^{2x + 1?} = 32 ^{x + 2} " align="absmiddle" class="latex-formula">
​
Mathematics
1 answer:
svet-max [94.6K]3 years ago
6 0

Answer:

x = 5

Step-by-step explanation:

<u>__________________________________________________________</u>

<u>FACTS TO KNOW BEFORE SOLVING</u> :-

  • a^x \times a^y = a^{x+y}
  • In an equation , if the bases are same in both L.H.S. & R.H.S. then , the power of the bases on both the sides of equation should be equal. For e.g. : a^x = a^y  ⇒  x = y  [∵ Bases are equal on both the sides]

<u>__________________________________________________________</u>

4 \times 8^{2x+1} = 32^{x+2}

Lets express it in terms of 2.

=> 2^2 \times 2^{3 (2x+1)} = 2^{5(x+2)}

=> 2^2 \times 2^{6x+3} = 2^{5x+10}

=> 2^{2 + 6x+3} = 2^{5x+10}

=> 2^{6x+5} = 2^{5x+10}

Here the bases on both the sides are equal. Hence ,

=> 6x + 5 = 5x + 10

=> 6x - 5x = 10 - 5

=> x = 5

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