3. 54

What is the constant rate of change in the equation? Y=5x+10

mezya [45]

Answer:

$m =5$

Step-by-step explanation:

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The "constant rate of change" is also known as the slope (in straight line equations).

The equation is in slope-intercept form.

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Slope-Intercept Form is:

$y = mx + b\\
\rule{150}{0.5}\\
\text{m - slope}\\
\text{b - Y-Intercept}$

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Since '5' takes up 'm's spot, it is the slope, or the constant rate of change.

================================================

Hope this helps.

6 0

2 years ago

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Find the appropriate rejection regions for the large-sample test statistic z in these cases. (Round your answers to two decimal

Usimov [2.4K]

Answer:

a) We have that the significance is given by $\alpha =0.01$ and we know that we have a right tailed test.

So for this case we need to look in the normal standard dsitribution a critical value that accumulates 1% of the area on the right and 99% of the area on the left. This value can be founded with the following excel code:

"=NORM.INV(1-0.01,0,1)"

And we got for this case $z_{crit}=2.33$

So then the rejection region would be $z>2.33$

b) We have that the significance is given by $\alpha =0.05$ , $\alpha/2 =0.025$ and we know that we have a two tailed test.

So for this case we need to look in the normal standard dsitribution a critical value that accumulates 2.5% of the area on the right and 97.5% of the area on the left. This value can be founded with the following excel code:

"=NORM.INV(1-0.025,0,1)"

And we got for this case $z_{crit}=\pm 1.96$

So then the rejection region would be $z>1.96 \cup z$

Step-by-step explanation:

Part a

We have that the significance is given by $\alpha =0.01$ and we know that we have a right tailed test.

So for this case we need to look in the normal standard dsitribution a critical value that accumulates 1% of the area on the right and 99% of the area on the left. This value can be founded with the following excel code:

"=NORM.INV(1-0.01,0,1)"

And we got for this case $z_{crit}=2.33$

So then the rejection region would be $z>2.33$

Part b

We have that the significance is given by $\alpha =0.05$ , $\alpha/2 =0.025$ and we know that we have a two tailed test.

So for this case we need to look in the normal standard dsitribution a critical value that accumulates 2.5% of the area on the right and 97.5% of the area on the left. This value can be founded with the following excel code:

"=NORM.INV(1-0.025,0,1)"

And we got for this case $z_{crit}=\pm 1.96$

So then the rejection region would be $z>1.96 \cup z$

7 0

3 years ago

What is (f-g)(x)? question equation show in picture

likoan [24]

Answer:

(f-g)(x) = x^4 - x^3 - 4x^2 - 3

Step-by-step explanation:

(f-g)(x) = x^4 - x^2 + 9 - (x^3 + 3x^2 + 12)

(f-g)(x) = x^4 - x^2 + 9 - x^3 - 3x^2 - 12

(f-g)(x) = x^4 - x^3 - 4x^2 - 3

7 0

3 years ago

What is the answer to ...8.42 x 9

3241004551 [841]

Answer:

75.78

Step-by-step explanation:

8.42*9=75.78

6 0

2 years ago

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BRAINLIEST AND 20 POINTS

Korvikt [17]

Tan(60)=Opposite or L /20cm

*20. *20

Tan(60)*20=L

34.64101615=L

34.64 (to the nearest hundredth of a meter or cm)

5 0

3 years ago

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