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2 years ago

What is the molarity of a 1.44 (m/v)% solution of an HCOOOH (Formic acid)?

1 answer:

8 0

This problem is providing the mass-volume percent of a formic acid solution so its molarity is required and found to be 0.313 M after the following calculations.

<h3>Molarity</h3>

In chemistry, units of concentration provide a measurable understanding of the relationship between the relative amounts of both solute and solvent. In the case of molarity, one must relate moles of solute and liters of solution as follows:

$M=\frac{mol\ solute}{Volume\ solution \ in \ L}$

In such a way, when given this mass-volume percent of 1.44% for the formic acid in the solution, one can assume there is 100 mL of solution and 1.44 g of solute (formic acid), which means one must convert the volume to liters and the mass to moles with:

$mol\ solute=\frac{1.44g}{46.03g/mol} =0.0313mol\\\\Volume\ in \liters: 100mL*\frac{1L}{1000mL}=0.100L$

Finally, we plug in these numbers in the equation for the calculation of molarity:

$M=\frac{0.0313mol}{0.100L}\\\\M=0.313M$

Learn more about molarity: brainly.com/question/10053901

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Answer : The specific heat of the metal is, $0.658J/g^oC$

Explanation :

In this problem we assumed that heat given by the hot body is equal to the heat taken by the cold body.

$q_1=-q_2$

$m_1\times c_1\times (T_f-T_1)=-m_2\times c_2\times (T_f-T_2)$

where,

$c_1$ = specific heat of metal = ?

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$m_1$ = mass of metal = 97 g

$m_2$ = mass of water = 122 g

$T_f$ = final temperature of mixture = $28.9^oC$

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$T_2$ = initial temperature of water = $20.0^oC$

Now put all the given values in the above formula, we get

$97g\times c_1\times (28.9-100)^oC=-122g\times 4.18J/g^oC\times (28.9-20.0)^oC$

$c_1=0.658J/g^oC$

Therefore, the specific heat of the metal is, $0.658J/g^oC$

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3 years ago

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I think the correct answer from the choices listed above is option A. A refracting telescope is made smaller than a reflecting telescope because small lenses cause less distortion in images than big lenses. <span> They are not subject to chromatic aberration because reflected light does not disperse according to wavelength.</span>

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3 years ago

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