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Jlenok [28]
3 years ago
11

Write a program that uses the Purchase class in 5.13. Set the prices to the following: Oranges: 10 for $2.99 Eggs: 12 for $1.69

Apples: 3 for $1.00 Watermelons: $4.39 each Bagels: 6 for $3.50 Set the purchased quantity to the following: 2 dozen oranges, 2 dozen eggs, 20 apples, 2 watermelons, 1 dozen bagels Display the total cost of the bill
Computers and Technology
1 answer:
Xelga [282]3 years ago
5 0

Answer:

Explanation:

The following program is written in Java. Using the program code from Purchase class in 5.13 I created each one of the fruit objects. Then I set the price for each object using the setPrice method. Then I set the number of each fruit that I intended on buying with the setNumberBought method. Finally, I called each objects getTotalCost method to get the final price of each object which was all added to the totalCost instance variable. This instance variable was printed as the total cost of the bill at the end of the program. My code HIGHLIGHTED BELOW

//Entire code is in text file attached below.

//MY CODE HERE

       DecimalFormat df = new DecimalFormat("0.00");

       oranges.setPrice(10, 2.99);

       oranges.setNumberBought(2*12);

       eggs.setPrice(12, 1.69);

       eggs.setNumberBought(2*12);

       apples.setPrice(3, 1);

       apples.setNumberBought(20);

       watermelons.setPrice(1, 4.39);

       watermelons.setNumberBought(2);

       bagels.setPrice(6, 3.50);

       bagels.setNumberBought(12);

       totalCost = oranges.getTotalCost() + eggs.getTotalCost() + apples.getTotalCost() + watermelons.getTotalCost() + bagels.getTotalCost();

       System.out.println("Total Cost: $" + df.format(totalCost));

   }

}

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2 years ago
Input 3 positive integers from the terminal, determine if tlrey are valid sides of a triangle. If the sides do form a valid tria
butalik [34]

Answer:

In Python:

side1 = float(input("Side 1: "))

side2 = float(input("Side 2: "))

side3 = float(input("Side 3: "))

if side1>0 and side2>0 and side3>0:

   if side1+side2>=side3 and side2+side3>=side1 and side3+side1>=side2:

       if side1 == side2 == side3:

           print("Equilateral Triangle")

       elif side1 == side2 or side1 == side3 or side2 == side3:

           print("Isosceles Triangle")

       else:

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   else:

       print("Invalid Triangle")

else:

   print("Invalid Triangle")

Explanation:

The next three lines get the input of the sides of the triangle

<em>side1 = float(input("Side 1: ")) </em>

<em>side2 = float(input("Side 2: ")) </em>

<em>side3 = float(input("Side 3: ")) </em>

If all sides are positive

if side1>0 and side2>0 and side3>0:

Check if the sides are valid using the following condition

   if side1+side2>=side3 and side2+side3>=side1 and side3+side1>=side2:

Check if the triangle is equilateral

<em>        if side1 == side2 == side3: </em>

<em>            print("Equilateral Triangle") </em>

Check if the triangle is isosceles

<em>        elif side1 == side2 or side1 == side3 or side2 == side3: </em>

<em>            print("Isosceles Triangle") </em>

Otherwise, it is scalene

<em>        else: </em>

<em>            print("Scalene Triangle") </em>

Print invalid, if the sides do not make a valid triangle

<em>    else: </em>

<em>        print("Invalid Triangle") </em>

Print invalid, if the any of the sides are negative

<em>else: </em>

<em>    print("Invalid Triangle")</em>

4 0
3 years ago
Discuss the major differences in two approaches ofprogramming i.e. Object oriented programming and structuredprogramming.
Romashka-Z-Leto [24]

Answer:

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____ [38]

Answer:

count_land = count_air = count_water = 0

while True:

   s = input("Enter a string: ")

   if s == "xxxxx":

       break

   else:

       if s == "land":

           count_land += 1

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           count_air += 1

       elif s == "water":

           count_water += 1

print("land: " + str(count_land))

print("air: " + str(count_air))

print("water: " + str(count_water))

Explanation:

*The code is in Python

Initialize the variables

Create a while loop that iterates until a specific condition is met. Inside the loop, ask the user to enter the string. If it is "xxxxx", stop the loop. Otherwise, check if it is "land", "air", or "water". If it is one of the given strings, increment its counter by 1

When the loop is done, print the number of strings entered in the required format

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bija089 [108]

Answer:

Explanation:My explanation is above my comment :)

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