3 years ago

I need help wit math rq pls! :(

1 answer:

6 0

David is correct because if the circle on the graph is filled in it means 17 or older but Lily’s represents older than 17

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Can anyone help! I have done 1 and 3 but I’m lost on the rest! Will give extra points!

MrRissso [65]

Answer:

i think thats good but for me umm so good hehe

4 0

2 years ago

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You can buy DVDs at a local store for 15.59 each. You can buy them at on online store for 13.99 each plus $6 shipping. How many

dalvyx [7]

Local(L) = 1 x (15.99)
Online(O) = (1 x 13.99) + 6

So use that equation until you find the same number.

L1=15.99
O1=19.99

L2=31.98
O2=33.98

L3=47.97
O3=47.97

And your answer will be three from local and three from online.

8 0

3 years ago

Are the triangles shown congruent?

boyakko [2]

Answer:

the second one i think

Step-by-step explanation:

because both have 2 sides with 1 angle

5 0

3 years ago

Normal Distribution. Cherry trees in a certain orchard have heights that are normally distributed with mu = 112 inches and sigma

Lubov Fominskaja [6]

Answer:

The probability that a randomly chosen tree is greater than 140 inches is 0.0228.

Step-by-step explanation:

Given : Cherry trees in a certain orchard have heights that are normally distributed with $\mu = 112$ inches and $\sigma = 14$ inches.

To find : What is the probability that a randomly chosen tree is greater than 140 inches?

Solution :

Mean - $\mu = 112$ inches

Standard deviation - $\sigma = 14$ inches

The z-score formula is given by, $Z=\frac{x-\mu}{\sigma}$

Now,

$P(X>140)=P(\frac{x-\mu}{\sigma}>\frac{140-\mu}{\sigma})$

$P(X>140)=P(Z>\frac{140-112}{14})$

$P(X>140)=P(Z>\frac{28}{14})$

$P(X>140)=P(Z>2)$

$P(X>140)=1-P(Z$

The Z-score value we get is from the Z-table,

$P(X>140)=1-0.9772$

$P(X>140)=0.0228$

Therefore, the probability that a randomly chosen tree is greater than 140 inches is 0.0228.

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3 years ago

Solve – 4y – 10 = 4(y - 3)

Snezhnost [94]

Answer:

y= 1/4

Step-by-step explanation:

7 0

3 years ago

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