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Blizzard [7]
3 years ago
10

Hey!! plz answer this question correctly plz plz plz im on a very tight time crunch thanks besties

Mathematics
2 answers:
soldier1979 [14.2K]3 years ago
7 0

Answer:

b is the answer I choose because it is going in-5

pav-90 [236]3 years ago
3 0

Answer:

B

Step-by-step explanation:

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Write a polynomial function with the real<br> zeros -3, 0, and 3.
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f(x)=x(x-3)(x+3)

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You make 42,500 and your spouse makes 37750 . using the 20% to 25% range , calculate the least and the greatest amount you shoul
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Suppose a and b are both non zero real numbers. Find real numbers c and d such that 1/a+ib= c+id
Thepotemich [5.8K]

\begin{gathered} c=\frac{a}{a^2+b^2} \\ d=\frac{-b}{a^2+b^2} \end{gathered}

Explanation

\frac{1}{a+bi}=c+di

Step 1

multiplicate by the conjugate

\begin{gathered} \frac{1}{a+bi}\cdot\frac{a-bi}{a+bi}=\frac{a-bi}{(a+bi)(a-bi)}=\frac{a-bi}{a^2-(bi)^2} \\ \frac{1}{a+bi}\cdot\frac{a-bi}{a+bi}=\frac{a-bi}{(a+bi)(a-bi)}=\frac{a-bi}{a^2-(-b^2)}=\frac{a-bi}{a^2+b^2} \end{gathered}

notice that

\begin{gathered} \frac{1}{a+bi}=\frac{a-bi}{a^2+b^2}=\frac{a}{a^2+b^2}-\frac{b}{a^2+b^2}i \\ \frac{a}{a^2+b^2}-\frac{b}{a^2+b^2}i=c+di \\ so \\  \end{gathered}\begin{gathered} c=\frac{a}{a^2+b^2} \\ d=\frac{-b}{a^2+b^2} \end{gathered}

I hope this helsp you

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