We are going to consider a rectangle with length called "a" and width "b" Then we know that perimeter is the sum of both sides 2*a + 2*b = 128 And also the following equation given by the question: a = 2*b + 3 So solving the first equation: 2*(2*b+3) + 2*b = 128 4*b+6+2*b=128 6*b = 122 b = 122/6 = 61/3 Then a=2*122/6+3 = 244/6+3 = 262/6 = 131/3 Solution: Length = 131/3 Width = 61/3
9) Separate the polygon into 2 shapes (a rectangle and triangle). Then plug in the formula for those 2 shapes separately and add the 2 areas.
First, the triangle's area = bh x 1/2 or bh/2.
b=5 and h=5, so 5x5/2 or 25/2 = 12.5.
Next, solve the area for the rectangle(lw=A). l=5 and 2=8, so 5x8=40.
Add 40 +12.5 = 52.5cm^2 (always include units).
10) It is similar to the last problem. You will separate the polygon into 2 shapes (a circle and a square), but this time you will subtract the area of the sector formed from the circle (draw a dotted line where the circle would be formed in the square).
So, the area of the square is 2x2=4ft^2.
area of a circle is (pi)r2 or (pi)2^2= 4pi or about 12.5ft^2.
4+12.5 = 16.5 ft^2.
Now, the area of the sector must be subtracted from the combination of the 2 areas found above.
The area of a sector is 2(pi)r x (C/360).
The angle is given as 90°, the radius is 2 ft. Now plug these into the equation.
2(pi)(2)x(90/360) = 3.14ft^2.
16.5-3.14= 13.4 ft^2.
<span>Acute triangles have angle measures that are less than 90°, so here are your three answers:
20°, 80°, and 80°
60°, 60°, and 60°
25°, 75°, and 80°
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The answer would have to be C because he cannot sell negative hats or infinitely many because he only has 300 to sell in the first place. Answer choice D makes no sense because there is no value of x that is less than zero and greater than 500.
Answer:
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