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MissTica
2 years ago
9

Fruh points to the butter dawg

Mathematics
2 answers:
SashulF [63]2 years ago
7 0

Answer:

Butter Dog?

Not a fan of too much butter but LOOOVE dogs......

topjm [15]2 years ago
3 0

Answer:

lets goooooooo

Step-by-step explanation:

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Evaluate the question​
mylen [45]

Answer:

A) 5/6

B) -67/30 (or) -2 7/30

A) -9/2 (or) -4 1/2

Step-by-step explanation:

A) 2/3(5)-5/2=3 1/3-5/2 = 10/3-5/2 = 20/6-15/6= 5/6

B) 2/3(2/5)-5/2= 4/15-5/2 = 8/30-75/30 = -67/30

A) 2/3(-3)-5/2=-2-5/2= -4 1/2

7 0
3 years ago
What is 11π/6 in degrees?
mojhsa [17]

Answer:

The answer is D which is 330

5 0
3 years ago
Read 2 more answers
I need help with this problem <br> x²﹣9x﹣15=﹣5
icang [17]

Move all terms to the left side and set equal to zero. Then set each factor equal to zero.

x=10,−1

7 0
3 years ago
Read 2 more answers
Write the faction ration for each of the following.<br> If m
Aleksandr-060686 [28]

Answer:

\tan D=\frac{7}{4},\\\\\sin D=\frac{7}{8.1}, \\\\\cos D=\frac{4}{8.1}, \\\\GI=5.0

Step-by-step explanation:

In any right triangle, the following is true:

The sine of any angle is equal to its opposite side divided by the hypotenuse of the triangle. (o/h)

The cosines of any angle is equal to its adjacent side divided by the hypotenuse. (a/h)

The tangent of any angle is equal to its opposite side divided by its adjacent side. (o/a)

Thus,

\text{3. }\\\tan D=\frac{7}{4},\\\\\sin D=\frac{7}{8.1}, \\\\\cos D=\frac{4}{8.1},

\text{4. }\tan 68^{\circ}=\frac{GI}{2},\\GI=2\tan68^{\circ}=4.95017370683\approx \boxed{5.0}

4 0
3 years ago
X<br> Find the value<br> of x. Show<br> 3<br> 10<br> your work.
pickupchik [31]

Step-by-step explanation:

<em>Hello</em><em>,</em><em> </em><em>there</em><em>!</em><em>!</em><em>!</em>

<em>Let</em><em> </em><em>ABC</em><em> </em><em>be</em><em> </em><em>a Right angled triangle</em><em>, </em>

<em>where</em><em>,</em><em> </em><em>AB</em><em> </em><em>=</em><em> </em><em>3</em>

<em>BC</em><em>=</em><em> </em><em>1</em><em>0</em>

<em>and</em><em> </em><em>AC</em><em>=</em><em> </em><em>x</em>

<em>now</em><em>,</em>

<em>As</em><em> </em><em>the</em><em> </em><em>triangle</em><em> </em><em>is</em><em> </em><em>a</em><em> </em><em>Right angled triangle</em><em>, </em><em>taking</em><em> </em><em>angle C</em><em> </em><em>as</em><em>refrence</em><em> </em><em>angle</em><em>.</em><em> </em><em>we</em><em> </em><em>get</em><em>,</em>

<em> </em><em>h</em><em>=</em><em> </em><em>AC</em><em> </em><em>=</em><em> </em><em>x</em>

<em>p</em><em>=</em><em> </em><em>AB</em><em> </em><em>=</em><em> </em><em>3</em>

<em>b</em><em>=</em><em> </em><em>BC</em><em>=</em><em> </em><em>1</em><em>0</em>

<em>now</em><em>,</em><em> </em><em>by</em><em> </em><em>Pythagoras</em><em> </em><em>relation we get</em><em>, </em>

<em>h =    \sqrt{ {p}^{2} +  {b}^{2}  }</em>

<em>or ,\: h =  \sqrt{ {3}^{2}  +  {10}^{2} }</em>

<em>by</em><em> </em><em>simplifying it we get</em><em>, </em>

<em>h</em><em> </em><em>=</em><em> </em><em>1</em><em>0</em><em>.</em><em>4</em><em>4</em><em>0</em><em>3</em><em>0</em>

<em>Therefore</em><em>, </em><em> </em><em>the</em><em> </em><em>answer is</em><em> </em><em>x</em><em>=</em><em> </em><em>1</em><em>0</em><em>.</em>

<em><u>Hope</u></em><em><u> </u></em><em><u>it helps</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em>

7 0
3 years ago
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