Answer:
If EFGH is an isosceles trapezoid,
if
EH=4x-27+
FG=x%2B9+
EG=3y%2B19
FH=11y-21
then EH=FG and EG=FH
set up equations:
4x-27=x%2B9 .......solve for x
4x-x=27%2B9
3x=36
x=36%2F3
3y%2B19=11y-21.......solve for y
11%2B19=11y-3y
30=8y
y=30%2F8
y=15%2F4
y=3.75
so,x=12 and y=3.75
you can also check the length of equal sides and equal diagonals:
EH=4%2A12-27+=21
FG=12%2B9+=21
EG=3%283.75%29%2B19=30.25
FH=11%283.75%29-21=30.25x=12
Step-by-step explanation:
Y = -4x + 2
3x + 2y = 6 (or in y-intercept form y=-3/2x + 3)
2x - y = 7 equals y = 2x -7 in y-intercept form. This means that the line has a positive slope and therefore goes upwards. This cannot be a potential equation because the line shown is clearly pointing downwards.
y=5 indicates that the line is a horizontal line that neither points upwards or downwards. This cannot be a potential equation because the line is pointing downwards.
The only possible equations left are y= -4x + 2 and 3x + 2y = 6, both of which graph a line pointing downwards because their slopes are negative. Hope this helps!
Answer:
the answer to that is -1i
Step-by-step explanation:
cause if you add negative and positve you get to subtract it and get the sign of the highest number
1.4 decameters. Hope this helped!
