Since it is the midpoint we can say:
12x - 1 = 8x +11
All we have do to is get all the x's alone on one side
12x - 1 = 8x + 11
12x = 8x + 12 (add both sides by 1)
4x = 12 (subtract both sides by 8x)
x = 3 (divide both sides to get what x is)
the question in English
Draw a rectangle having the base congruent to the nine sevenths of the height.
Let
b-------> the base of rectangle
h-------> the height of rectangle
we know that
b=(9/7)*h-------> this is the equation to obtain the base of the rectangle for a given height
examples
1) for h=7 units
b=(9/7)*7-------->b=9 units
the dimensions are 9 units x 7 units------> see the attached figure
2) for h=5 units
b=(9/7)*5-------->b=(45/7) units
the dimensions are (45/7) units x 5 units
The answer in Italian
Facciamo
b-------> base del rettangolo
h-------> altezza del rettangolo
Noi sappiamo che
b=(9/7)*h-------> questa è l'equazione per ottenere la base del rettangolo per una determinata altezza
esempi
1) per h=7 units
b=(9/7)*7-------->b=9 units
le dimensioni sono 9 units x 7 units----->
vedere la figura allegata
2) per h=5 units
b=(9/7)*5-------->b=(45/7) units
le dimensioni sono (45/7) units x 5 units
Answer: y = 3 (x -4)^3
Step-by-step explanation: horizontal shift of 4 units to the right (subtract 4 units from the x): y = 3(x - 4)^3
Vertical shift 3 units down (subtract 3 units from the function): y = 3(x - 4)^3 - 3
No. It is not. Only what's inside counts.
Answer:
14.4 lb
Step-by-step explanation:
In a see-saw in equilibrium, the torque generated by one side needs to be the same generated in the other side. The torque is calculated by the product between the mass and the distance to the center of the see-saw.
The torque generated by the child is:
T1 = 60 * 3 = 180 lb*feet
So, the torque generated by the weight needs to be higher than T1 in order to lift the child.
The lowest mass is calculated when the mass is in the maximum distance, that is, 12.5 feet from the center.
So, we have that:
T2 = 180 = mass * 12.5
mass = 180/12.5 = 14.4 lb
So the lowest weight is 14.4 lb