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ivann1987 [24]
3 years ago
15

Two functions are defined as shown. f(x) =-1/2 x – 2 g(x) = –1 Which graph shows the input value for which f(x) = g(x)?

Mathematics
2 answers:
Alchen [17]3 years ago
5 0

Answer:

The second graph

Step-by-step explanation:

Just did it!!

Natalka [10]3 years ago
4 0

Answer:

See attachment.

Step-by-step explanation:

The given functions are:

f(x) =  -  \frac{1}{2}x - 2

and g(x)=-1

To find the x-value of the point of intersection of the two functions, we equate the two functions and solve for x.

-  \frac{1}{2}x - 2 = -1

x + 4 = 2

x = 2 - 4 =  - 2

The graph that shows the input value for which f(x)=g(x) is the graph which shows the point of intersection of f(x) and g(x) to be at x=-2.

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One is significantly fatter than the other and has more friction
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4 years ago
The pregnancy length in days for a population of new mothers can be approximated by a normal distribution with a mean of days an
solniwko [45]

Answer:

(a) 283 days

(b) 248 days

Step-by-step explanation:

The complete question is:

The pregnancy length in days for a population of new mothers can be approximated by a normal distribution with a mean of 268 days and a standard deviation of 12 days. ​(a) What is the minimum pregnancy length that can be in the top 11​% of pregnancy​ lengths? ​(b) What is the maximum pregnancy length that can be in the bottom ​5% of pregnancy​ lengths?

Solution:

The random variable <em>X</em> can be defined as the pregnancy length in days.

Then, from the provided information X\sim N(\mu=268, \sigma^{2}=12^{2}).

(a)

The minimum pregnancy length that can be in the top 11​% of pregnancy​ lengths implies that:

P (X > x) = 0.11

⇒ P (Z > z) = 0.11

⇒ <em>z</em> = 1.23

Compute the value of <em>x</em> as follows:

z=\frac{x-\mu}{\sigma}\\\\1.23=\frac{x-268}{12}\\\\x=268+(12\times 1.23)\\\\x=282.76\\\\x\approx 283

Thus, the minimum pregnancy length that can be in the top 11​% of pregnancy​ lengths is 283 days.

(b)

The maximum pregnancy length that can be in the bottom ​5% of pregnancy​ lengths implies that:

P (X < x) = 0.05

⇒ P (Z < z) = 0.05

⇒ <em>z</em> = -1.645

Compute the value of <em>x</em> as follows:

z=\frac{x-\mu}{\sigma}\\\\-1.645=\frac{x-268}{12}\\\\x=268-(12\times 1.645)\\\\x=248.26\\\\x\approx 248

Thus, the maximum pregnancy length that can be in the bottom ​5% of pregnancy​ lengths is 248 days.

8 0
3 years ago
What is the area of a regular heptagon with side length of 6 meters and a distance from the to the vertex of 6 meters? round you
Ahat [919]
Apothem = side length / 2*tan(180 / number of sides)
apothem = side length / 2*tan (180 / 7)
apothem = 6 / (2*tan( <span> <span> <span> 25.7142857143</span></span></span>))
apothem = 6 / 2*0.48157
<span><span><span>apothem = 6.2296239384 </span> </span> </span>

Polygon area = (# of sides * side length * apothem) / 2
Polygon area = ( 7 * 6 * <span>6.2296239384) / 2
</span><span><span><span>Polygon area = 130.8221027064 </span> </span> </span> 



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Read 2 more answers
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Orlov [11]

Answer:

line a and b are parallel, there is no perpendicular lines

Step-by-step explanation:

Looking at the slope of each line, you can identify whether the lines are parallel, perpendicularlar, or neither.

When the slopes are the same, they are parallel.

When the slopes have opposite sign and numerator and denominator flipped, they are perpendicular. Ex. \frac{a}{b} and -\frac{b}{a} are perpendicular slopes.

Finding slope is using the formula: \frac{y_{2}-y_{1}  }{x_{2} -x_{1} }

Line a has slope  \frac{3-4}{4-0} = -\frac{1}{4}

Line b also has slope -\frac{1}{4}

Line c has slope 2

Since slope of line a and b are same, they are parallel.

Line c is not perpendicular to line a and b because the slope should have opposite sign and numerator and denominator flipped, which is 4 not 2.

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