![\bf f(x)=(x-6)e^{-3x}\\\\ -----------------------------\\\\ \cfrac{dy}{dx}=1\cdot e^{-3x}+(x-6)-3e^{-3x}\implies \cfrac{dy}{dx}=e^{-3x}[1-3(x-6)] \\\\\\ \cfrac{dy}{dx}=e^{-3x}(19-3x)\implies \cfrac{dy}{dx}=\cfrac{19-3x}{e^{3x}}](https://tex.z-dn.net/?f=%5Cbf%20f%28x%29%3D%28x-6%29e%5E%7B-3x%7D%5C%5C%5C%5C%0A-----------------------------%5C%5C%5C%5C%0A%5Ccfrac%7Bdy%7D%7Bdx%7D%3D1%5Ccdot%20e%5E%7B-3x%7D%2B%28x-6%29-3e%5E%7B-3x%7D%5Cimplies%20%5Ccfrac%7Bdy%7D%7Bdx%7D%3De%5E%7B-3x%7D%5B1-3%28x-6%29%5D%0A%5C%5C%5C%5C%5C%5C%0A%5Ccfrac%7Bdy%7D%7Bdx%7D%3De%5E%7B-3x%7D%2819-3x%29%5Cimplies%20%5Ccfrac%7Bdy%7D%7Bdx%7D%3D%5Ccfrac%7B19-3x%7D%7Be%5E%7B3x%7D%7D)
set the derivative to 0, solve for "x" to get any critical points
keep in mind, setting the denominator to 0, also gives us critical points, however, in this case, the denominator will never be 0, so... no critical points from there
there's only 1 critical point anyway, and do a first-derivative test on it, check a number before it and after it, to see what sign the derivative has, and thus, whether the graph is going up or down, to check for any extrema
Answer:
Step-by-step explanation: Use the slope formula which is y2-y1
x2-x1
Answer: (0,1)
Step-by-step explanation:
If 
and 
are two point son a coordinate plane and (x,y) dividing it in a ratio of m: n.
Then , the coordinates of (x,y) is given by :-
Given : On a coordinate plane, a line is drawn from point A to point B. Point A is at (2, - 3) and point B is at (- 4, 9).
Then , the x- and y- coordinates of point E, which partitions the directed line segment from A to B into a ratio of 1:2 :
Hence, the x- and y- coordinates of point E = (0,1)
Answer:
Step-by-step explanation:
w+ -4 2/5= 1/10
W = 1/10 + 4 2/5
W = 1/10 + 22/5
W = (1 + 44)/10
W = 45/10
W = 9/2
W = 4 1/2
Answer:
62 and 56 or 59 and 59
Step-by-step explanation:
62, 62, 56
or
62, 59, 59
