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Slav-nsk [51]
2 years ago
7

A student made the following chart to prove that AB2 + BC2 = AC2:

Mathematics
1 answer:
aalyn [17]2 years ago
4 0

Answer:

Solution:

Given : In triangle ABC right angled at B.

To Prove :

Construction: Draw B D perpendicular AC.

Proof: 1. Triangle ABC is similar to triangle BDC 1. Angle ABC = Angle BDC and Angle BCA = Angle BCD  

2. = AC × DC 2. BC ÷ DC = AC ÷ BC because triangle ABC is similar to triangle BDC  

3. Triangle ABC is similar to triangle ABD 3. Angle ABC = Angle BAD and Angle BAC = Angle ABD  

4.   = AC × AD 4. AB ÷ AD = AC ÷ AB because triangle ABC is similar to triangle ABD  

5.

= AC (AD + DC)  

6. Adding Statement 1 and Statement 2  

7.

→→→Statement 3 is incorrect.It should be replaced by, Angle ABC = Angle ADB and Angle B AC = Angle BAD .

hope i could help also if u have time please mark me as brainlest

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Answer:

La ecuación genérica para un círculo centrado en el punto (a, b), de radio R, es:

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La gráfica de esta circunferencia se puede ver en la imagen de abajo.

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