A student made the following chart to prove that AB2 + BC2 = AC2:

Mathematics

1 answer:

aalyn [17]3 years ago

4 0

Answer:

Solution:

Given : In triangle ABC right angled at B.

To Prove :

Construction: Draw B D perpendicular AC.

Proof: 1. Triangle ABC is similar to triangle BDC 1. Angle ABC = Angle BDC and Angle BCA = Angle BCD

2. = AC × DC 2. BC ÷ DC = AC ÷ BC because triangle ABC is similar to triangle BDC

3. Triangle ABC is similar to triangle ABD 3. Angle ABC = Angle BAD and Angle BAC = Angle ABD

4. = AC × AD 4. AB ÷ AD = AC ÷ AB because triangle ABC is similar to triangle ABD

= AC (AD + DC)

6. Adding Statement 1 and Statement 2

→→→Statement 3 is incorrect.It should be replaced by, Angle ABC = Angle ADB and Angle B AC = Angle BAD .

hope i could help also if u have time please mark me as brainlest

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