Answer:
216 g of NO
Explanation:
We begin from the reaction:
4NH₃ + 5O₂ → 4NO + 6H₂O
We determine the limiting reactant with the moles of each reactant:
4 moles of ammonia react to 5 moles of oxygen
Our 7.2 moles of ammonia may react to (7.2 . 5) /4 = 9 moles
It's ok because we have 9.6 moles of oxygen. 0.6 moles still remain.
5 moles of oxygen react to 4 moles of NH₃
Our 9.6 moles of oxygen may react to (9.6 . 4) /5 = 7.68 moles
We only have 7.2 moles of NH₃ and we need 7.68; so there is no enough ammonia and that's our limiting reagent.
Now we determine the moles of product.
4 moles of ammonia can produce 4 moles of NO
Definetely our 7.2 moles, will produce 7.2 moles of oxide.
We convert to mass: 7.2 mol . 30 g/mol = 216 g
