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3 years ago

If you had 15 moles of Oxygen (O2), how many moles of water (H2O) would you be able to make?

Chemistry

1 answer:

larisa [96]3 years ago

5 0

Answer:

30 moles of water will produced.

Explanation:

Given data:

Number of moles of O₂ react = 15 mol

Number of moles of water formed = ?

Solution:

Chemical equation:

2H₂ + O₂ → 2H₂O

Now we will compare the moles of water with oxygen.

O₂ : H₂O

1 : 2

15 : 2×15 = 30 mol

30 moles of water will produced.

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a solution with a transmittance of 0.44 is analyzed in a spectrophotometer with 6% stray light. calculate the absorbance reporte

IgorLugansk [536]

The absorbance reported by the defective instrument was 0.3933.

Absorbance A = - log₁₀ T

Tm = transmittance measured by spectrophotometer

Tm = 0.44

Absorbance reported in this equipment = -log₁₀ (0.44) = 0.35654

True absorbance can be calculated by true transmittance, Tm = T+S(α-T)

S = fraction of stray light = 6%= 6/100 = 0.06

α= 1, ideal case

T = true transmittance of the sample

Tm = T+S(α-T)

now, T= Tm-S/ 1-S = 0.44-0.06/ 1-0.06 = 0.404233

therefore, actual reading measured is A = -log₁₀ T = -log₁₀ (0.404233)

i.e; 0.3933

To know more about transmittance click here:

brainly.com/question/17088180

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1 year ago

1.The layers of the atmosphere are characterized by changes in ?

bearhunter [10]

Answer:

1 temperature 2 weather 3 the stratosphere 4 decreases 5 increases

Explanation:

8 0

3 years ago

Read 2 more answers

To find the volume of a ring, the water displacement method was used.

ohaa [14]

Answer:

4 cm³?

Explanation:

68-64

4 0

3 years ago

A wooden artifact from a Chinese temple has a 14C activity of 42.8 counts per minute as compared with an activity of 58.2 counts

Arlecino [84]

Answer : The age of the artifact is, $2.54\times 10^3\text{ years}$

Explanation :

Half-life = 5715 years

First we have to calculate the rate constant, we use the formula :

$k=\frac{0.693}{5715\text{ years}}$

$k=1.21\times 10^{-4}\text{ years}^{-1}$

Now we have to calculate the time taken to decay.

Expression for rate law for first order kinetics is given by:

$t=\frac{2.303}{k}\log\frac{a}{a-x}$

where,

k = rate constant

t = time taken by sample = ?

a = initial activity of the reactant = 58.2 counts per minute

a - x = activity left after decay process = 42.8 counts per minute

Now put all the given values in above equation, we get

$t=\frac{2.303}{1.21\times 10^{-4}}\log\frac{58.2}{42.8}$

$t=2540.5\text{ years}=2.54\times 10^3\text{ years}$

Therefore, the age of the artifact is, $2.54\times 10^3\text{ years}$

4 0

3 years ago

If we were to continue to add more and more naoh from our original stock solution, what is the highest ph that could be reached?

Novay_Z [31]

If its a acid it will be 3 or if its a alkali then 14 or neutral then 7

7 0

3 years ago