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storchak [24]
3 years ago
8

If you had 15 moles of Oxygen (O2), how many moles of water (H2O) would you be able to make?

Chemistry
1 answer:
larisa [96]3 years ago
5 0

Answer:

30 moles of water will produced.

Explanation:

Given data:

Number of moles of O₂ react = 15 mol

Number of moles of water formed = ?

Solution:

Chemical equation:

2H₂ + O₂      →     2H₂O

Now we will compare the moles of water with oxygen.

                  O₂           :          H₂O

                   1             :            2

                   15           :           2×15 = 30 mol

30 moles of water will produced.

                   

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Viefleur [7K]
<span>0.298 M The balanced equation for the reaction is HCl + NaOH = H2O + NaCl So for every mole of NaOH used, one mole of HCl is neutralized. So let's determine how many moles of NaOH we used. That will simply be the volume (in liters) of solution multiplied by the molarity. So 0.0493 L * 0.151 mol/L = 0.0074443 mol Because of that 1:1 ratio, we now know that 0.0074443 moles of HCl was in the sample. Since molarity is moles per liter, a little division will give us the molarity of the HCl solution. So 0.0074443 mol / 0.025 L = 0.297772 mol/M = 0.297772 M Rounding to 3 significant figures gives 0.298 M.</span>
7 0
3 years ago
Consider the above reaction using 25.0 mL of tert-butyl alcohol (d = 0.786 g/mL) with 60.0 mL of concentrated hydrobromic acid (
Liono4ka [1.6K]

Answer:

Theoretical yield: 36,3g

Percent yield: 71,9%

Explanation:

The reaction of tert-butyl alcohol with hydrobromic acid to produce tert-butyl bromide is a 1:1 reaction.

Moles of tert-butyl alcohol in 25,0 mL are:

25,0mL × (0,786g / mL) × (1mol / 74,12g) = <em><u>0,265 moles of tert-butyl alcohol</u></em>

Moles of hydrobromic acid are:

60,0mL× 47,0% × (1,49g / mL) × (1mol / 80,91g) = <em><u>0,519 moles of HBr</u></em>

As moles of tert-butyl alcohol are less than moles of HBr, limiting reactant is tert-butyl alcohol.

Theoretical yield of tert-butyl bromide in grams is:

0,265 moles × (137,02g / 1mol) = <em>36,3g</em>

Percent yield:

26,1g / 36,3g × 100 = <em>71,9%</em>

The reactions are in the image.

There are many ways to produce alkyl halides from primary and secondary alcohols. The reaction in this case is the Appel reaction.

The reaction of tertiary alkyl halides may undergo a hydrolysis reaction -under proper conditions- to form an alcohol and a hydrogen halide.

I hope it helps!

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4 years ago
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The formation of an ester is an exothermic reaction. Therefore, a decrease in the temperature of the reaction will favour the production of ester.

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How many moles of bromine (Br) atoms are in a sample of 2.03 × 1024 atoms?
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3 0
4 years ago
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