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natta225 [31]
2 years ago
11

Factor 2x^4 + 2x^3 - x^2 - x

Mathematics
1 answer:
MAVERICK [17]2 years ago
8 0
2x^3(x+1)-x(x+1)
(2x^3-x)(x+1)
x(2x^2-1)(x+1)
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K² = 76<br><br>What is the answer?​
Dmitry_Shevchenko [17]

Answer:

k = 2 √ 19 , − 2 √ 19

Step-by-step explanation:

Take the root of both sides and solve.

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2 years ago
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Math! :( no links answer correct for brainliest!
dem82 [27]
90 squareroot 2
In decimal form it’s 127.27922
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3 years ago
Two solutions of different concentrations of acid are mixed creating 40 mL of a solution that is 32% acid. One-quarter of the so
Georgia [21]
In order to construct this equation, we will use the variables:
V to represent mixture volume (40 ml)
C to represent mixture concentration (0.32)
v₁ to represent volume of first solution (40 / 4 = 10 ml)
c₁ to represent concentration of first solution (0.2)
v₂ to represent the volume of the second solution (40 * 3/4 = 30 ml)
c₂ to represent the concentration of the second solution 


We know that the total amount of substance, product of the volume and concentration, in the final solution is equal to the individual amounts in the two given solutions. Thus:
VC = v₁c₁ +  v₂c₂
40(0.32) = 10(0.2) + 30c
6 0
3 years ago
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A tank currently holds 5 gallons of water. It is being filled at the rate of 1/4 gallon per minute. How long will it take for th
Verdich [7]
So we know the tank already has 5 gallons and we need 9. This means we need 4 more gallons in order to fill up the tank.

If 1/4 gallon is being filled per minute we need to find out how many 1/4 gallons makes up 4 gallons in total.

4 of the 1/4 gallons makes up 1 whole gallon. So since we need 4 whole gallons we would need 16 of the 1/4 gallons.

This means that it will take 16 minutes for the tank to hold 9 gallons of water. 
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3 years ago
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1.
denis-greek [22]

Answer:

Part a) AB=15\ cm

Part b) AB=11.1\ cm

Part c) AB=3/5\ cm

Part d) AB=3s\ cm

Step-by-step explanation:

see the attached figure to better understand the question

we know that

To find the length of the image after a dilation, multiply the length of the pre-image by the scale factor

Part a) we have

The scale factor is 5

The length of the pre-image is 3 cm

therefore

The length of the image AB after dilation is

3(5)=15\ cm

Part b) we have

The scale factor is 3.7

The length of the pre-image is 3 cm

therefore

The length of the image AB after dilation is

3(3.7)=11.1\ cm

Part c) we have

The scale factor is 1/5

The length of the pre-image is 3 cm

therefore

The length of the image AB after dilation is

3(1/5)=3/5\ cm

Part d) we have

The scale factor is s

The length of the pre-image is 3 cm

therefore

The length of the image AB after dilation is

3(s)=3s\ cm

7 0
3 years ago
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