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Veronika [31]
3 years ago
7

The Chief Information Officer (CIO) has determined the company’s new PKI will not use OCSP. The purpose of OCSP still needs to

be addressed. Which of the following should be implanted?A. Build an online intermediate CA.B. Implement a key escrow.C. Implement stapling.D. Install a CRL.
Computers and Technology
1 answer:
Step2247 [10]3 years ago
8 0

Answer:

B. Implement a key escrow.

Explanation:

A key escrow can be defined as a data security method of storing very essential cryptographic keys.

Simply stated, key escrow involves a user entrusting his or her cryptographic key to a third party for storage.

As a standard, each cryptographic key stored or kept in an escrow system are directly linked to the respective users and are encrypted in order to prevent breach, theft or unauthorized access.

Hence, the cryptographic keys kept in an escrow system are protected and would not be released to anyone other than the original user (owner).

In this scenario, the Chief Information Officer (CIO) has determined the company's new public key infrastructure (PKI) will not use online certificate status protocol (OCSP). However, the purpose of online certificate status protocol (OCSP) still needs to be addressed. Thus, what should be implemented is a key escrow because the online certificate status protocol (OCSP) is an internet protocol used for maintaining the security of a server and obtaining a digital certificate that has been revoked.

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Answer:

In Python:

entry = input("Sentence: ")

while True:

   if entry.count(",") == 0:

       print("Error: No comma in string")

       entry = input("Sentence: ")

   elif entry.count(",") > 1:

       print("Error: Too many comma in input")

       entry = input("Sentence: ")

   else:

       ind = entry.index(',')+1

       if entry[ind].isnumeric() == False:

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           entry = input("Sentence: ")

       else:

           break

print("Valid Input")

Explanation:

This prompts the user for a sentence

entry = input("Sentence: ")

The following loop is repeated until the user enters a valid entry

while True:

This is executed if the number of commas is 0

<em>    if entry.count(",") == 0:</em>

<em>        print("Error: No comma in string")</em>

<em>        entry = input("Sentence: ")</em>

This is executed if the number of commas is more than 1

<em>    elif entry.count(",") > 1:</em>

<em>        print("Error: Too many comma in input")</em>

<em>        entry = input("Sentence: ")</em>

This is executed if the number of commas is 1

   else:

This calculates the next index after the comma

       ind = entry.index(',')+1

This checks if the character after the comma is a number

       if entry[ind].isnumeric() == False:

If it is not a number, the print statement is executed

<em>            print("Comma not followed by an integer")</em>

<em>            entry = input("Sentence: ")</em>

If otherwise, the loop is exited

<em>        else:</em>

<em>            break</em>

This prints valid input, when the user enters a valid string

print("Valid Input")

Note that: entry = input("Sentence: ") <em>is used to get input</em>

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Answer:

Explanation:

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Answer:

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7 0
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