Binary search involves searching a sorted list
The number of values that will be examined is 15
<h3>How to determine the number of examined values</h3>
The equation that calculates the number of values that will be examined is:
Where n represents the number of values to examine and N represents the number of time stamps
So, we have:
Take the log of both sides
Apply the laws of logarithm
![[n - 1]\log(2) = 4](https://tex.z-dn.net/?f=%5Bn%20-%201%5D%5Clog%282%29%20%3D%204)
Divide both sides y log(2)
The next integer greater than 13.2 is 14.
So, we have:
Add 1 to both sides
Hence, the number of values that will be examined is 15
Read more about binary search at:
brainly.com/question/20411780
Answer:
private void printArray(int[] arr){ //0
System.out.print("["); //1
for(int k : arr){ //2
System.out.print(k + ", "); //3
}
System.out.println("]"); //4
}
Explanation:
This method should get you started. Your teacher may want a different format or a different type of loop. If you haven't learned for loops yet don't use them that'd be suspicious ;)
What I did:
0: This is the method heading with one parameter for the 1D array. If you need to access it in a different class change private to public.
1: This prints the [ with no line break
2: This is an enhanced for loop to iterate through each element in a 1D array. Alternatively, a normal for loop looks like this:
for (int i = 0; i < arr.length; i++)
instead of retrieving the variable with the enhanced for, you'd have to use arr[i] instead of k in this scenario.
3: This prints the value in each pass of the loop along with a comma and a space.
4: This adds the ] with a line break when the loop is completed
Hope this helps you get started :D comment if you need further help
Answer:
A polyribosome (or polysome or ergasome) is a group of ribosomes bound to an mRNA molecule like “beads” on a “thread”. It consists of a complex of an mRNA molecule and two or more ribosomes that act to translate mRNA instructions into polypeptides.
Answer:
it is a complete routine of life without it we cannot do time management
Explanation:
mark me brainliest ❤
Answer:
import java.util.*;
public class Country
{
public static void main(String args[])
{
char ch,temp;
int flag = 0;
String country;
ArrayList<String> countries = new ArrayList<String>();
Scanner sc = new Scanner(System.in);
do
{
System.out.println("enter the country you have visited:\t");
country = sc.next();
for(int i=0;i<countries.size();i++)
{
if(countries.get(i).equals(country))
{
System.out.println("you have already entered the country");
flag = 1;
break;
}
}
if(flag == 0)
{
countries.add(country);
flag = 0;
}
System.out.println("want to add another country(y/n):\t");
ch = sc.next().charAt(0);
}while(ch!='n');
Collections.sort(countries);
System.out.println("Countries you have visited:\t"+countries);
System.out.println("Total number of contries visited:"+countries.size());
}
}
Explanation:
