Answer:

Step-by-step explanation:
Given


Required
Determine the part left
The part left is calculated using:



Take LCM



Answer:
its a,b,c, or d
Step-by-step explanation:
A is the answer. it’s the answer
Answer:
X= 2
Step-by-step explanation:
10 + x = -12
X = 12 - 10
X = 2