Point t slope form:
y + y value = m (x + x value) where m is the gradient
Parallel line must have the same gradient as the two lines never meet, so the gradient must be 4. This eliminates option B and D.
Remember that point-slope form is still an equation, so the values of both sides must be equal. So let's substitute the given coordinates.
Option A:
y-6=4(x+2)
-6-6 (-12) does not equal to 4(-2+2) (0)
Option C:
y+6=4(-2+2)
-6+6 (0) = 4(-2+2) (0)
Therefore, option C is your answer.
Answer:
38
Step-by-step explanation:
The simplest (almost trivial) solution is to add the two inequalities:
(x +3y) +(3x +2y) ≤ (13) +(25)
4x +5y ≤ 38
The maximum value of P is 38.
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Perhaps more conventionally, you can graph the equations, or solve them to find the point of intersection of their boundary lines. That point is (x, y) = (7, 2), which is the point in the doubly-shaded solution space that gives the maximum value of P (puts the objective function line farthest from the origin).
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In the attached graph, we have been a little sloppy, not applying the constraints that x, y ≥ 0. For the purpose of finding the requested solution, that is of no consequence.