Question

Between which two integers does -√46 appear on the number line please write in words

Answer 1

Answer:   -√46 is between -7 and -6

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Explanation:

List out the perfect squares

• 1^2 = 1
• 2^2 = 4
• 3^3 = 9
• 4^2 = 16
• 5^2 = 25
• 6^2 = 36
• 7^2 = 49
• 8^2 = 64

and so on. We can see that 46 is between 6^2 = 36 and 7^2 = 49.

We can say 6^2 < 46 < 7^2

Applying the square root to all three sides leads us to 6 < sqrt(46) < 7

Now multiply all three sides by -1. This will flip the inequality signs

We go from

6 < sqrt(46) < 7

to

-6 > -sqrt(46) > -7

It might help to order things from smallest to largest to get this

-7 < -sqrt(46) < -6

This means -sqrt(46) is between -7 and -6 on the number line

See the diagram below.

Answer 2

Answer:

Step-by-step explanation:

First notice that -√46 lies between -√49 and -√36, that is, between

                                                              -7   and  -6.  

Here all three numbers are negative because they lie to the left of zero (0) on the number line.