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2 years ago

Liam invested $1,200 in an account paying an interest rate of 8,75% % compounded monthly. Camila invested $1,200 in an

Mathematics

2 answers:

Licemer1 [7]2 years ago

7 0

Answer: 430

430 in delta math

Step-by-step explanation:

svet-max [94.6K]2 years ago

6 0

2102.53 welcome hope that help

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7 - 2x - x4

neonofarm [45]

Answer: (see explanation)

Step-by-step explanation:

terms: 7, 2x, x4

leading coefficient: 7

constant term: 7

I'm sorry I'm unsure how to solve the last question.

8 0

2 years ago

The verticle of a triangle are (2, 18) (-2, -4), and (6,12.

Sergeu [11.5K]

so the triangle has the vertices of (2, 18) (-2, -4), and (6,12), that gives us the endpoints for each line of

(2, 18) , (-2, -4)

(-2, -4) , (6,12)

(6,12) , (2, 18)

$\bf (\stackrel{x_1}{2}~,~\stackrel{y_1}{18})\qquad (\stackrel{x_2}{-2}~,~\stackrel{y_2}{-4}) \\\\\\ slope = m\implies \cfrac{\stackrel{rise}{ y_2- y_1}}{\stackrel{run}{ x_2- x_1}}\implies \cfrac{-4-18}{-2-2}\implies \cfrac{-22}{-4}\implies \cfrac{11}{2} \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-18=\cfrac{11}{2}(x-2) \\\\\\ y-18=\cfrac{11}{2}x-11 \implies \blacktriangleright y=\cfrac{11}{2}x+7 \blacktriangleleft$

$\bf (\stackrel{x_1}{-2}~,~\stackrel{y_1}{-4})\qquad (\stackrel{x_2}{6}~,~\stackrel{y_2}{12}) \\\\\\ slope = m\implies \cfrac{\stackrel{rise}{ y_2- y_1}}{\stackrel{run}{ x_2- x_1}}\implies \cfrac{12-(-4)}{6-(-2)}\implies \cfrac{12+4}{6+2}\implies \cfrac{16}{8}\implies 2 \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-(-4)=2[x-(-2)] \\\\\\ y+4=2(x+2)\implies y+4=2x+4\implies \blacktriangleright y=2x \blacktriangleleft$

$\bf (\stackrel{x_1}{6}~,~\stackrel{y_1}{12})\qquad (\stackrel{x_2}{2}~,~\stackrel{y_2}{18}) \\\\\\ slope = m\implies \cfrac{\stackrel{rise}{ y_2- y_1}}{\stackrel{run}{ x_2- x_1}}\implies \cfrac{18-12}{2-6}\implies \cfrac{6}{-3}\implies -2 \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-12=-2(x-6) \\\\\\ y-12=-2x+12\implies \blacktriangleright y=-2x+24 \blacktriangleleft$

6 0

2 years ago

Which equation has no solution? A 2(x+1)=1 B 2(x+1)=2x+2 C 2(x+1)=2x+1 D 2(x+1)=2

Veseljchak [2.6K]

Answer:

C) 2(x+1)=2x+1 ( No Solution )

Step-by-step explanation:

$2(x+1)=1\\\cfrac{2\left(x+1\right)}{2}=\frac{1}{2}\\x+1=\cfrac{1}{2}\\ x+1-1=\frac{1}{2}-1\\\boxed{x=-\frac{1}{2}}$

$2(x+1)=2x+2\\2x+2=2x+2\\2x+2-2=2x+2-2\\2x=2x\\2x-2x=2x-2x\\0=0$

$2(x+1)=2x+1 \\2x+2=2x+1\\2x+2-2=2x+1-2\\2x=2x-1\\2x-2x=2x-1-2x\\0=-1\\\boxed{No\:Solution}$

$2(x+1)=2\\\cfrac{2\left(x+1\right)}{2}=\cfrac{2}{2}\\x+1=1\\x+1-1=1-1\\x=0$

4 0

2 years ago

If f(x) = x^2 is reflected over the x-axis and the shifted 4 units down, what is the equation of the new function, g(x)?

NARA [144]

Answer:

g(x) = -x² - 4

Step-by-step explanation:

In this case, we are only changing <em>a </em>(reflection and vertical shrink/stretch) and <em>k </em>(vertical movement)

<em>k </em>= -4 because we are moving 4 units down

<em>a </em>= -1 because we are just reflecting over the x-axis

6 0

3 years ago

Which Of the following pairs of functions are inverse of each other?

damaskus [11]

One way is to solve for the inverse of the first function

remember, to solve, replace f(x) or g(x) with y, switch x and y, solve for y and replace it with $f^{-1} (x)$

$f(x)=x/2+8\\y=x/2+8\\x=y/2+8\\x-8=y/2$

$2x-16=y$

$f^{-1}=2x-16$

nope, not A

<h3>What is the inverse function?</h3>

The inverse function of a function f is a function that undoes the operation of f. The inverse of f exists if and only if f is bijective, and if it exists, is denoted by $f^{-1}.$