C is your answer i hope u got it right
Class A: 6v + 8b = 202
Class B: 12v + 16b = 284
Solve using the elimination method:
since 6v and 12v are perfect for elimination, multiply the class A equation by 2 so that the van variable cancels out:
12v + 16b = 404
12v + 10b = 284
Then subtract the bottom equation from the top:
6b = 120
b = 20
Now you know that each bus can hold 20 students.
Just plug this into one of the original equations to solve for vans:
6v + 8(20) = 202
6v + 160 = 202
6v = 42
v=7
So then you know that each van can hold 7 students.
Check:
12 (7) + 10 (20) = 284
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I agree. All real numbers except -1.
D. 5 5/6
Volume = l * b * h
= 2 1/2 * 3 1/2 * 2/3
= 5/2 * 7/2 * 2/3
= 35/6
= 5 5/6
Answer:
The cost to fill the new family size box will be
Step-by-step explanation:
we know that
If two figures are similar, then the ratio of its volumes is equal to the scale factor elevated to the cube
Let
z-----> the scale factor
we have
so
To find the new cost multiply the original cost by the scale factor elevated to the cube
The new volume would be