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3 years ago

10

Dominic and Tyler collected soda cans to raise money. Dominic collected 700 cans and Tyler collected 7000 cans. The number of ca

ns Tyler collected is how many times greater than the number of cans Dominic collected?

1 answer:

Crank3 years ago

4 0

It should be ten times greater since,

700x10=7000

So ten times greater.

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In right triangle ABC, AB=6, BC=12, and m∠A=90°. What is the value of cot C?

VikaD [51]

I believe C it is 45

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3 years ago

Which list shows all the factors of 16?

geniusboy [140]

Answer:

C

Step-by-step explanation:

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8 0

2 years ago

The length of a rectangle is 1 more yd than twice the width, and the area of the rectangle is 66 yd squared. Find the dimensions

Salsk061 [2.6K]

Width = 5.5yd

Length = 12yd

<u>Explanation:</u>

Area of rectangle = $66yd^{2}$

Let width of the rectangle = b ,

So, length = 2b+1

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$66yd^{2} = (2b+1) X b\\66yd^{2} = 2b^{2} + b\\2b^{2} +b-66 = 0\\$

On solving the equation we get,

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l = 12yd

Hence,

Width = 5.5yd

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6 0

3 years ago

Evaluate the Expression when b=3<br><br><img src="https://tex.z-dn.net/?f=%20%7Bb%7D%5E%7B2%7D%20%20-%206b%20-%205" id="TexFormu

meriva

Now let’s evaluate this down if b=3 then you do 3x3 because b is squared which equals 9 then we do 6b which is 18, so 9-18 is (-9) then we do -9 - 5 which is -14

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2 years ago

How do I solve this

anastassius [24]

$\bf \cfrac{x+2}{x^2+6x-7}$ so, that function is "defined", ok, what values of "x" are not in the domain, namely, what values can "x" take on and not make the function "undefined", well, you know, if we end up with a 0 at the denominator, like $\bf \cfrac{x+2}{0}$ then, we'd have an "undefined" expression...so... any values of "x" that make the denominator 0, are not really the ones we want, and thus they'd be excluded from the domain.

so, hmm which are those? let's check, let's set the denominator to 0, and solve for "x".

$\bf x^2+6x-7=0\implies (x+7)(x-1)=0\implies x=
\begin{cases}
-7\\
1
\end{cases}
\\\\\\
\textit{let's check, } x=-7\quad \cfrac{(-7)+2}{(-7)^2+6(-7)-7}\implies \cfrac{-5}{49-42-7}\implies \cfrac{-5}{0}
\\\\\\
x=1\quad \cfrac{(1)+2}{(1)^2+6(1)-7}\implies \cfrac{3}{1+6-7}\implies \cfrac{-3}{0}$

7 0

3 years ago