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Greeley [361]
3 years ago
10

Arrange the following in order of increasing bond strength of the carbon oxygen bond: Group of answer choices Carbon monoxide &l

t; carbon dioxide < carbonate ion Carbonate ion < carbon monoxide < carbon dioxide Carbon dioxide < carbon monoxide < carbonate ion Carbon dioxide < carbonate ion < carbon monoxide carbonate ion < carbon dioxide < carbon monoxide Carbon monoxide < carbonate ion < carbon dioxide Carbonate ion < carbon monoxide < carbon dioxide
Chemistry
1 answer:
Irina-Kira [14]3 years ago
3 0

Answer:

carbonate ion < carbon dioxide < carbon monoxide

Explanation:

Bond strength depends on the bond order of a bond. The higher the bond order, the greater the bond strength since shorter bonds are stronger than longer bonds.

The carbonate ion has a bond order of 1.33, carbon dioxide has a bond order of 2 while carbon monoxide has a bond order of 3.

Since the compound with the highest C-O  bond order has the strongest C-O bond, then carbon monoxide possesses the strongest C-O bond.

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inysia [295]
<h2>0.72 mol/L</h2>

Explanation:

       \textrm{Molarity of a solution}=\frac{\textrm{Number of moles of solvent}}{\textrm{Volume of solution in Liters}}

       We are given a 2.50L solution which contains 135g of KCl.

       To calculate number of moles of KCl present, we need to find it's molar mass from charts. Molar Mass of KCl is known to be 74.55\frac{g}{Mol}.

       Number of moles of KCl present = \frac{\textrm{Given weight}}{\textrm{Molar Mass}}\textrm{ = }\frac{135g}{74.55\frac{g}{Mol}}\textrm{ = }1.81087mol

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∴ Molarity of given KCl solution = 0.72\frac{mol}{L}

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I am hoping that these answers have satisfied your queries and it will be able to help you, thank you and have a nice day.

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