I think is oxygen that what i think
Answer:
412 g Cl₂
General Formulas and Concepts:
<u>Atomic Structure</u>
- Reading a Periodic Table
- Moles
- Avogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.
<u>Stoichiometry</u>
- Using Dimensional Analysis
Explanation:
<u>Step 1: Define</u>
[Given] 3.50 × 10²⁴ molecules Cl₂
[Solve] grams Cl₂
<u>Step 2: Identify Conversions</u>
Avogadro's Number
[PT] Molar Mass of Cl - 35.45 g/mol
Molar Mass of Cl₂ - 2(35.45) = 70.9 g/mol
<u>Step 3: Convert</u>
- [DA] Set up:

- [DA] Divide/Multiply [Cancel out units]:

<u>Step 4: Check</u>
<em>Follow sig fig rules and round. We are given 3 sig figs.</em>
412.072 g Cl₂ ≈ 412 g Cl₂
2:7 ratio of ethane to O2 = 15:x 9solve for x)
x=52.5 mol O2
Answer:
The class of this compound is <u>aldehyde or ketone (i).</u>
Explanation:
Absorption peak at 1720 cm-1 shows the presence of a carbonyl group, possibly an aldehyde or ketone with C=O bond.
Further information on molecular formula would be required for structural elucidation.
Answer:
1.5g
Explanation:
According to this question, the amount of copper required to obtain copper sulfide in a 4:1 is 6g. This means that the ratio of copper to sulfur in the compound (copper sulfide) is 4:1.
Hence, to calculate the amount of sulfur required for the reaction to obtain copper sulfide using the above ratio, we say:
1/4 of the amount of copper required (6g)
= 1/4 × 6
= 6/4
= 1.5g of sulfur is required for the reaction to obtain carbon sulfide.