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Complete Question
The life of a semiconductor laser at a constant power is normally distributed with a mean of 7,000 hours and a standard deviation of 600 hours. If three lasers are used in a product and they are assumed to fail independently, the probability that all three are still operating after 7,000 hours is closest to? Assuming percentile = 95%
Answer:
0.125
Step-by-step explanation:
Assuming for 95%
z score for 95th percentile = 1.645
We find the Probability using z table.
P(z = 1.645) = P( x ≤ 7000)
= P(x<Z) = 0.95
After 7000 hours = P > 7000
= 1 - P(x < 7000)
= 1 - 0.95
= 0.05
If three lasers are used in a product and they are assumed to fail independently, the probability that all three are still operating after 7,000 hours is calculated as:
(P > 7000)³
(0.05)³ = 0.125
Answer:
18 children
Step-by-step explanation:
Given
<em>Required (missing part of the question):</em>
<em>Number of children that will be able to go to the zoo if 8 adult tickets are purchased</em>
<em>The graph is missing. However, the question can be solved without the graph.</em>
<em />
From the question and equation, we can deduce the following:
- x represents adults
- y represents children
So, when 8 adult tickets were sold.
This means
Substitute 8 for x in
Subtract 96 from both sides
Solve for y
<em>This means that 18 children will be able to go</em>
He went upstream 3 hours and downstream two. 4x3=12 6x2=12
He went 24 miles.
Answer:
125
Step-by-step explanation:
The ratio is 5:3 so we divide the 75 by 3 to get 1 part
1 part = 75
75 x 5 = 125
125 strawberries were sold :)
Answer: (1+2a)^2 or (1+2a)(1+2a)
Step-by-step explanation:
