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tiny-mole [99]
3 years ago
11

It’s just #14 & #15, HELLOOOOOOOOOOO BEUTIFULLL CAN U HELP!?

Mathematics
1 answer:
Vsevolod [243]3 years ago
5 0

Answer:

14) 29.7

15) Longer leg= 12.1

Hypotenuse=14

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A class has 6 boys and 15 girls. what is the ratio of boys to girls
butalik [34]

Answer: 6:15

Step-by-step explanation:


3 0
2 years ago
Read 2 more answers
Is (-4,4) the solution of the system. 4x+5y>-6 and -2x+7y>20
nikklg [1K]

Answer:

  It is <em>a</em> solution, one of an infinite number of solutions.

Step-by-step explanation:

You can check to see if the given point is in the solution set:

  4(-4) +5(4) = -16 +20 = 4 > -6 . . . . yes

  -2(-4) +7(4) = 8 +28 = 36 > 20 . . . yes

The offered point satisfies both inequalities, so is in the solution set. It is not <em>the</em> solution, but is one of an infinite number of solutions.

7 0
3 years ago
Which expression is equal to 5^4⋅5^8 ? 512 54 52 5−4
KiRa [710]

Answer is 5^12 which is choice A (assuming you meant to put the ^ symbol)

The bases are the same (both are 5), so you add the exponents: 4+8 = 12. The base stays the same the entire time.

So, 5^4*5^8 = 5^(4+8) = 5^12

3 0
3 years ago
8-x+4-2-8x= What does x equal
goldfiish [28.3K]

Answer:

-9x + 10

Step-by-step explanation:

3 0
3 years ago
Expand using the properties and rules for logarithms
malfutka [58]

Consider expression \log_{\frac{1}{2}}\left(\dfrac{3x^2}{2}\right).

1. Use property

\log_a\dfrac{b}{c}=\log_ab-\log_ac.

Then

\log_{\frac{1}{2}}\left(\dfrac{3x^2}{2}\right)=\log_{\frac{1}{2}}3x^2-\log_{\frac{1}{2}}2.

2. Use property

\log_abc=\log_ab+\log_ac.

Then

\log_{\frac{1}{2}}\left(\dfrac{3x^2}{2}\right)=\log_{\frac{1}{2}}3x^2-\log_{\frac{1}{2}}2=\log_{\frac{1}{2}}3+\log_{\frac{1}{2}}x^2-\log_{\frac{1}{2}}2.

3. Use property

\log_ab^k=k\log_ab.

Then

\log_{\frac{1}{2}}\left(\dfrac{3x^2}{2}\right)=\log_{\frac{1}{2}}3+\log_{\frac{1}{2}}x^2-\log_{\frac{1}{2}}2=\log_{\frac{1}{2}}3+2\log_{\frac{1}{2}}x-\log_{\frac{1}{2}}2.

4. Use property

\log_{a^k}b=\dfrac{1}{k}\log_ab.

Then

\log_{\frac{1}{2}}\left(\dfrac{3x^2}{2}\right)=\log_{\frac{1}{2}}3+2\log_{\frac{1}{2}}x-\log_{\frac{1}{2}}2=\log_{\frac{1}{2}}3+2\log_{\frac{1}{2}}x-\log_{2^{-1}}2=\\ \\=\log_{\frac{1}{2}}3+2\log_{\frac{1}{2}}x+\log_22=\log_{\frac{1}{2}}3+2\log_{\frac{1}{2}}x+1.

Answer: correct option is B.

7 0
3 years ago
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