Multiply everything by 5:
5(-10)=5(-4/5y+6)
Then solve:
-30=-4y+30
Then subtract 30 from both sides:
-60=4y
Then divide:
15=y
That would be 40000 because you would move the decimal place over 4 places
Answer:
The minimum sample size required is 71.
Step-by-step explanation:
The (1 - <em>α</em>)% confidence interval for population mean is:

The margin of error for this interval is:

It is provided that the population standard deviation <em>σ</em> can be estimated by the sample standard deviation <em>s</em>.
The given information is:
<em>s</em> = 18000,
Margin of error = $4200.
Confidence level = 95%
The <em>z</em>-value for 95% confidence level is,

*Use a <em>z</em>-table for the critical value.
Compute the sample size required as follows:

![n=[\frac{z_{\alpha/2}\times \sigma }{MOE}]^{2}](https://tex.z-dn.net/?f=n%3D%5B%5Cfrac%7Bz_%7B%5Calpha%2F2%7D%5Ctimes%20%5Csigma%20%7D%7BMOE%7D%5D%5E%7B2%7D)
![=[\frac{18000\times 1.96}{4200}]^{2}](https://tex.z-dn.net/?f=%3D%5B%5Cfrac%7B18000%5Ctimes%201.96%7D%7B4200%7D%5D%5E%7B2%7D)

Thus, the minimum sample size required is 71.
Answer:
whats the question i can't really see it
Step-by-step explanation: