$=\sqrt{4^2}\times\sqrt{2^2\cdot3}$
$=4\times2\sqrt3=8\sqrt3$
What is a quarter to eight
1 answer:
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Answer:
see explanation and attachment
Step-by-step explanation:
(1) y = -x + 2
so slope is -1 and y-intercept is (0,2)
(2) 2x - y = 7
y = 2x - 7
so slope is 2 and y-intercept is (0,-7)
Answer:
x=0
x=10
x=24
Step-by-step explanation:
f(x) = -.05x^2 + x +6
The initial value is 6 ( Let x=0 and f(0) = 6)
f(x) = -.05( x^2 -20 x -120)
I plotted the equation and maximum is at x=10 and the zero is at x=25
