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scoundrel [369]
3 years ago
11

Which s.i. units are most accurate to use when measuring

Mathematics
1 answer:
liraira [26]3 years ago
6 0
A. length = meter = m (base)
b. volume = cubic meter = m³ (derived)
c. mass = kilogram = kg (base)
d. temperature = kelvin = K (base)
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I've done the sketch but am unsure as what my next steps should be?
Grace [21]

Answer:

you gotta see whats up with it

Step-by-step explanation:

7 0
2 years ago
I need help please. The question is already there. Tysm. 20 points.
Bess [88]

Answer:

$109 and 35%

Step-by-step explanation:

49.05 is the sale price and the discount is 55%. What’s the original price?

price/ 1- discount

49.05/ 1 - 0.55

49.05/ 0.45

109

for the other part

to find the discount subtract final price from original price

94 - 61.10 = 32.9

Which would be 35% in percent form.

5 0
2 years ago
A simple random sample of size nequals10 is obtained from a population with muequals68 and sigmaequals15. ​(a) What must be true
valentina_108 [34]

Answer:

(a) The distribution of the sample mean (\bar x) is <em>N</em> (68, 4.74²).

(b) The value of P(\bar X is 0.7642.

(c) The value of P(\bar X\geq 69.1) is 0.3670.

Step-by-step explanation:

A random sample of size <em>n</em> = 10 is selected from a population.

Let the population be made up of the random variable <em>X</em>.

The mean and standard deviation of <em>X</em> are:

\mu=68\\\sigma=15

(a)

According to the Central Limit Theorem if we have a population with mean <em>μ</em> and standard deviation <em>σ</em> and we take appropriately huge random samples (<em>n</em> ≥ 30) from the population with replacement, then the distribution of the sample mean will be approximately normally distributed.

Since the sample selected is not large, i.e. <em>n</em> = 10 < 30, for the distribution of the sample mean will be approximately normally distributed, the population from which the sample is selected must be normally distributed.

Then, the mean of the distribution of the sample mean is given by,

\mu_{\bar x}=\mu=68

And the standard deviation of the distribution of the sample mean is given by,

\sigma_{\bar x}=\frac{\sigma}{\sqrt{n}}=\frac{15}{\sqrt{10}}=4.74

Thus, the distribution of the sample mean (\bar x) is <em>N</em> (68, 4.74²).

(b)

Compute the value of P(\bar X as follows:

P(\bar X

                    =P(Z

*Use a <em>z</em>-table for the probability.

Thus, the value of P(\bar X is 0.7642.

(c)

Compute the value of P(\bar X\geq 69.1) as follows:

Apply continuity correction as follows:

P(\bar X\geq 69.1)=P(\bar X> 69.1+0.5)

                    =P(\bar X>69.6)

                    =P(\frac{\bar X-\mu_{\bar x}}{\sigma_{\bar x}}>\frac{69.6-68}{4.74})

                    =P(Z>0.34)\\=1-P(Z

Thus, the value of P(\bar X\geq 69.1) is 0.3670.

7 0
3 years ago
Help
Art [367]

\huge\fbox{Answer ☘}

\bold{3( \frac{27}{8} ) {}^{ \frac{2}{3}  \times  - 1}  = 2( \frac{32}{243} ) {}^{2x} }\\  \\3(( \frac{3}{2} ) {}^{3} ) {}^{ \frac{2}{3} \times  - 1 }  = 2(( \frac{2}{3} ) {}^{5} ) {}^{2x}  \\\\ 3( \frac{3}{2} ) {}^{2 \times  - 1}  = 2( \frac{2}{3} ) {}^{10x}  \\\\ 3( \frac{2}{3} ) {}^{2}  = 2( \frac{2}{3} )  {}^{10x}  \\\\ 3( \frac{4}{9} ) = 2( \frac{4}{9} ) {}^{5x}  \\\\\bold\pink{ comparing \: powers }\\\\5x = 1 \\\\ \bold\blue{x =  \frac{1}{5} }

hope helpful~

5 0
2 years ago
Jake cut a round gelatin dessert into 8 equal parts. five of the pieces were eaten . what is the angle measure of the dessert th
Alchen [17]

Answer:

3/8

Step-by-step explanation:

8-5=3

8 0
3 years ago
Read 2 more answers
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