Answer:
See picture and explanation below
Explanation:
In the attached picture you have the answer for this.
In the first step, we have an acid base reaction between HCN and NaOH. When this happens, its formed the following:
HCN + NaOH --------> CN⁻ + H₂O + Na⁺
As a second step, The CN⁻ attacks the carbonile group in the cyclopentane. This causes to open the double bond, and then, the Cyano enters the molecule.
The final step is another acid base reaction, where the oxygen substracts a hydrogen atom of the water in the medium, and then, the alcohol group is formed. With this step, the cyanohydrin is finally formed. See the mechanism below in the picture.
Hope this helps
A. because a chemical change is something that's changing
Answer:
I would say b hope this helps
Explanation:
have a good day btw i had this question before:D
There are 1.93 x 10²⁴ particles
<h3>Further explanation</h3>
Given
3.2 moles of Neon gas
Required
Number of particles
Solution
The mole is the number of particles(molecules, atoms, ions) contained in a substance
<em>1 mol = 6.02.10²³ particles
</em>
Can be formulated
N=n x No
N = number of particles
n = mol
No = Avogadro's = 6.02.10²³
So the number of particles for 3.2 moles :
N = 3.2 x 6.02.10²³
N = 1.93 x 10²⁴
or
we can describe it using Avogadro's number conversion factor
Answer:
378mL
Explanation:
The following data were obtained from the question:
Pressure (P) = 99.19 kPa
Temperature (T) = 28°C
Number of mole (n) = 0.015 mole
Volume (V) =...?
Next, we shall convert the pressure and temperature to appropriate units. This is illustrated below:
For Pressure:
101.325 KPa = 1 atm
Therefore, 99.19 kPa = 99.19/101.325 = 0.98 atm
For Temperature:
T(K) = T(°C) + 273
T(°C) = 28°C
T(K) = 28°C + 273 = 301K.
Next we shall determine the volume of N2. The volume of N2 can be obtained by using the ideal gas equation as shown below:
PV = nRT
Pressure (P) = 0.98 atm
Temperature (T) = 301K
Number of mole (n) = 0.015 mole
Gas constant (R) = 0.0821atm.L/Kmol.
Volume (V) =...?
0.98 x V = 0.015 x 0.0821 x 301
Divide both side by 0.98
V = (0.015 x 0.0821 x 301) /0.98
V = 0.378 L
Finally, we shall convert 0.378 L to millilitres (mL). This is illustrated below:
1L = 1000mL
Therefore, 0.378L = 0.378 x 1000 = 378mL
Therefore, the volume of N2 collected is 378mL
