From the calculations, the final momentum of B is 8.16 m/s
<h3>What is conservation of linear momentum?</h3>
According to the principle of the conservation of linear momentum, the momentum before collision is equal to the total momentum after collision.
This implies that;
MaUa + MbUb = MaVa + MaVa
Substituting values;
(0.08 kg * 0.5 m/s) + (0.05 kg * 0 m/s) = (0.08 kg * −0.1 m/s) + (0.05 kg * v)
0.4 = -0.008 + 0.05v
v = 8.16 m/s
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Answer:
Explanation:
Given
mass of body
radius of circle
Time Period
suppose is the angular velocity of revolution
therefore
Centripetal acceleration
therefore centripetal
For this question, we determine first the x and y components of the distances.
3 blocks north:
x - component = +3 ; y-component = 0
4 blocks northeast:
x - component = (cos 45°)(4 blocks) = 2.83 blocks
y - component = (cos 45°)(4 blocks) = 2.83 blocks
5 blocks west:
x-component = -5 ; y-component = 0
Then, we add up all the x-components and all the y-components
x-component (sum) = 0.83
y-component (sum) = 2.83
Then, we determine the magnitude of the block by the equation below.
m = √(x² + y²) = √(0.83² + 2.83²) ≈ 2.95 blocks
Thus, the displacement from the original position is approximately equal to 2.95 blocks.