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stepan [7]
2 years ago
9

Which word best describes the tone of the poem "Sir Isaac Newton"? A. magical B. mystical C. series D. humorous

Physics
2 answers:
salantis [7]2 years ago
8 0
The answer to this question is b mystical
erma4kov [3.2K]2 years ago
6 0

a. magical i hope it help

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A new roller coaster contains a loop-the-loop in which the car and rider are completely upside down. If the radius of the loop i
Mila [183]

Answer:

11.4 m/s

Explanation:

The expression for the Centripetal acceleration is :

a=\frac{v^2}{R}

Where, a is the accleration

v is the velocity around circumference of circle

R is radius of circle

In the given question,

a = g = Acceleration due to gravity as the car is at top = 9.81\ m/s^2

v = ?

R = 13.2 m

So,

9.81=\frac{v^2}{13.2}

v^2=9.81\times {13.2}

<u>v = 11.4 m/s</u>

8 0
3 years ago
why can scientists ignore the forces of attraction between particles in a gas under ordinary conditions?
Anna35 [415]
<span>The particles in a gas are apart and moving fast, so the forces of attraction are too weak to have a noticeable effect.</span>
5 0
3 years ago
Read 2 more answers
Matter is anything that has
Svetlanka [38]

Answer:

Space

Explanation:

Hope this helped

8 0
3 years ago
Which of the following is not a colligative property? a. osmotic pressure b. lattice energy c. vapor-pressure lowering d. boilin
Gre4nikov [31]

Answer:

b) lattice energy

Explanation:

A solution is said to have colligative property when the property depends on the solute present in the solution.

Colligative property depend upon on the solute particle or the ion concentration not on the identity of solute.

osmotic pressure, vapor pressure lowering , boiling point elevation and freezing point lowering all depend upon solute concentration so they will not have colligative property so, the answer remains option 'b' which is lattice energy.

8 0
2 years ago
As seen in the figure, a bullet with mass of 15.0-g is fired vertically and penetrates a block with mass of 2.5-kg and the block
rodikova [14]

Answer:

KE = 2.03 J

Explanation:

After impact, the kinetic energy of the bullet+block will convert to potential energy

½mv² = mgh

v = √(2gh) = √(2(9.81)(0.00500) = 0.0981 m/s

conservation of momentum during the collision

0.015u + 2.50(0) = (2.50 + 0.015)(0.0981)

u = 16.4481 m/s

KE = ½mv² = ½(0.015)16.4481² = 2.0290499...

KE = 2.03 J

4 0
3 years ago
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