The formula is
(theta)/360 · 2(pi)r
theta is the given angle
r is radius of the circle
Answer:
Therefore the concentration of salt in the incoming brine is 1.73 g/L.
Step-by-step explanation:
Here the amount of incoming and outgoing of water are equal. Then the amount of water in the tank remain same = 10 liters.
Let the concentration of salt be a gram/L
Let the amount salt in the tank at any time t be Q(t).

Incoming rate = (a g/L)×(1 L/min)
=a g/min
The concentration of salt in the tank at any time t is =
g/L
Outgoing rate =



Integrating both sides

[ where c arbitrary constant]
Initial condition when t= 20 , Q(t)= 15 gram


Therefore ,
.......(1)
In the starting time t=0 and Q(t)=0
Putting t=0 and Q(t)=0 in equation (1) we get









Therefore the concentration of salt in the incoming brine is 1.73 g/L
Answer:
i would go for a but im not really sure. sorry if incorrect
Step-by-step explanation:
10 grapefruit in each box. If the grower shipped 20,400 boxes. You would have to multiply to find out the total number of grapefruit.
20,400 boxes times 10 in each box.
20,400 x 10 = 204,000
204,000 grapefruit were shipped.
Hope this helps. :)