Question

If x = t^3 and y = t^2 - 2 , what is y in terms of x?

Answer 1

Answer:

E

Step-by-step explanation:

You have to get t^2 in the first equation.

x = t^3                         Take the cube root of both sides

$\sqrt[3]{x} = \sqrt[3]{t^3}$

$\sqrt[3]{x}=t$                         Now square both sides

$(\sqrt[3]{x})^2 = t^2$

$x^\frac{2}{3} = t^2$

Now you can substitute into the second equation

y = t^2 - 2

y = $x^\frac{2}{3}$ - 2

E