If mZDEF = 115, then what are mZFEG and mZHEG? The diagram is not to scale.

Please help. im taking the test right now and i need the answer!!

photoshop1234 [79]

Answer:

Either -2 or + 1

Step-by-step explanation:

I can't tell u exactly because I don't know the answer choices.

6 0

3 years ago

Please help me with this !! I REALLY need to have good grades because...Back story I had my phone and I broke it and I can't get

nevsk [136]

Answer:

Transformation include reflecting and dilating of points

The scale factor from PQR to P'Q'R' is 1/4

The coordinates of P"Q"R" are P"=(-1,0) Q"=(0,-1) R"=(2,-1) .

PQR and P′'Q′'R′' are not congruent

The points are given as:

p=(4,0)

q=(0,-4)

r=(-8,-4)

p'=(1,0)

q'=(0-1)

r'=(-2,-1)

(a)The scale factor from PQR to P'Q'R

To do this, we make use of corresponding sides QR and Q'R

So, the scale factor (k) is:

k=q'r'/qr

k=2/8

k=1/4

(b) The coordinates of P"Q"R from reflecting P'Q'R' about the y-axis

The rule of this transformation is:

(x,y)--------(-x,y)

So, we have:

p"=(-1,0)

q"=(0,-1)

r"=(2,-1)

(c) Are triangle PQR and P"Q'R" congruent?

No they are not

This is so because

PQR was dilated by 1/4 to get P'Q'R

P'Q'R' and P"Q"R" are congruent

Hence, PQR and P′'Q′'R′' are not congruent

Step-by-step explanation:

4 0

3 years ago

What is the value of x?

Paul [167]

Answer:

x= 85 is the answer. ( because exterior angle of a triangle is equal to 2 non adjacent interior angle of a triangle..)

3 0

3 years ago

Mark's school is selling tickets to the annual dance competition. On the first day of ticket sales the school sold 4 senior tick

erica [24]

The cost of each senior ticket is $ 5 and cost of each child ticket is $ 12

Solution:

Let "a" be the price of each senior ticket

Let "b" be the price of each child ticket

On the first day of ticket sales the school sold 4 senior tickets and 4 child tickets for a to total of 68

Thus a equation is framed as:

4 senior tickets x price of each senior ticket + 4 child tickets x price of each child ticket = 68

$4 \times a + 4 \times b = 68$

4a + 4b = 68 ---------- eqn 1

The school took in 120 on the second day by selling 12 senior tickets and 5 child tickets

Similarly, we frame a equation as:

$12 \times a + 5 \times b = 120$

12a + 5b = 120 ---------- eqn 2

Let us solve eqn 1 and eqn 2

Multiply eqn 1 by 3

12a + 12b = 204 -------- eqn 3

Subtract eqn 2 from eqn 3

12a + 12b = 204

12a + 5b = 120

( - ) --------------

7b = 84

b = 12

Substitute b = 12 in eqn 1

4a + 4(12) = 68

4a + 48 = 68

4a = 20

a = 5

Thus cost of each senior ticket is $ 5 and cost of each child ticket is $ 12

4 0

3 years ago

Find the volume of the solid formed by revolving the region bounded by LaTeX: y = \sqrt{x} y = x and the lines LaTeX: y = 1 y =

Strike441 [17]

Answer:

The volume is:

$\displaystyle\frac{37\pi}{10}$

Step-by-step explanation:

See the sketch of the region in the attached graph.

We set the integral using washer method:

$\displaystyle\int_a^b\pi r^2dx$

Notice here the radius of the washer is the difference of the given curves:

$x-\sqrt{x}$

So the integral becomes:

$\displaystyle\int_1^4\pi(x-\sqrt{x})^2dx$

We solve it:

Factor $\pi$ out and distribute the exponent (you can use FOIL):

$\displaystyle\pi\int_1^4x^2-2x\sqrt{x}+x\,dx$

Notice: $x\sqrt{x}=x\cdot x^{1/2}=x^{3/2}$

So the integral becomes:

$\displaystyle\pi\int_1^4x^2-2x^{3/2}+x\,dx$

Then using the basic rule to evaluate the integral:

$\displaystyle\pi\left[\frac{x^3}{3}-\frac{2x^{5/2}}{5/2}+\frac{x^2}{2}\right|_1^4$

Simplifying a bit:

$\displaystyle\pi\left[\frac{x^3}{3}-\frac{4x^{5/2}}{5}+\frac{x^2}{2}\right|_1^4$

Then plugging the limits of the integral:

$\displaystyle\pi\left[\frac{4^3}{3}-\frac{4(4)^{5/2}}{5}+\frac{4^2}{2}-\left(\frac{1}{3}-\frac{4}{5}+\frac{1}{2}\right)\right]$

Taking the root (rational exponents):

$\displaystyle\pi\left[\frac{4^3}{3}-\frac{4(2)^{5}}{5}+\frac{4^2}{2}-\left(\frac{1}{3}-\frac{4}{5}+\frac{1}{2}\right)\right]$

Then doing those arithmetic computations we get:

$\displaystyle\frac{37\pi}{10}$

6 0

3 years ago