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3 years ago

Does any body know how to program a video game? Because a got an idea

Computers and Technology

1 answer:

klio [65]3 years ago

8 0

Answer:

well you have to take classes or use easier systems like scratch

Explanation:

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Use the drop-down menu to identify which command is used to do the activities.

Ronch [10]

Answer:

1. save and save as

2. save as

3. save as

4.save as

5. save and save as

Explanation:

just took did the question

6 0

3 years ago

At what depth does an employer need to use a protection system to ensure the safety of workers in a trench or excavation?

nevsk [136]

Trench 4 foot or deeper and must be located 25 foot within eachother

3 0

3 years ago

Read 2 more answers

Derive an expression for the boolean function L(a,c) whose output is 1 when the light would be on. Note that two of the switches

Naddik [55]

Answer:

Following are the solution to the given question:

Explanation:

Please find the graph image in the attachment file.

In the sequence, they recognize how modules are divided and elements were introduced in parallel. L(a,c) is thus going to also be

$\to a*c + a'*c' = ac + a'c'$

It allows, ideally, to bring a thumbs up.

3 0

2 years ago

Which term means a cryptography mechanism that hides secret communications within various forms of data?.

andrezito [222]

Answer:

anything u have daling

Explanation:

6 0

2 years ago

You also learn in class that one kilobyte of computer memory will hold about 2/3 of a page of typical text (without formatting).

Travka [436]

Answer:

The flashdrive can hold 35389 400-pages-books

Explanation:

If $\frac{2}{3}$ of a page occupies 1 kB of memory, we can calculate how much memory a book will take

$2/3kB=1 page\\ x kB=400 pages\\266.67 kB=400 pages$

Now that we know that a book average file size is about 266,67 kB, we calculate how many of them can a 9 GB flash drive hold.

To do the calculation, we have to know how many kilobytes are in 9 gigabytes.

There is 1024 kilobytes in a megabyte, and 1024 megabytes in a gigabyte, so:

$Memory_{in _kilobytes}^{} =1024\frac{kilobytes}{megabytes} *1024\frac{megabytes}{gigabytes}*9=9437184 kilobytes$

Finally, knowing the average file size of a book and how much memory in kilobytes the 9 GB flash drive holds, we calculate how many books can it hold.

$Books=\frac{Flash drive memory}{Filesize of a book} =\frac{9437184kilobytes}{266.67\frac{kilobytes}{book} } =35389,4 books$

The flashdrive can hold 35389 400-pages-books, or 14155776 pages of typical text.

8 0

3 years ago