Answer:
Less
Explanation:
Since [Cu(NH3)4]2+ and [Cu(H2O)6]2+ are Octahedral Complexes the transitions between d-levels explain the majority of the absorbances seen in those chemical compounds. The difference in energy between d-levels is known as ΔOh (ligand-field splitting parameter) and it depends on several factors:
- The nature of the ligand: A spectrochemical series is a list of ligands ordered on ligand strength. With a higher strength the ΔOh will be higher and thus it requires a higher energy light to make the transition.
- The oxidation state of the metal: Higher oxidation states will strength the ΔOh because of the higher electrostatic attraction between the metal and the ligand
A partial spectrochemical series listing of ligands from small Δ to large Δ:
I− < Br− < S2− < Cl− < N3− < F−< NCO− < OH− < C2O42− < H2O < CH3CN < NH3 < NO2− < PPh3 < CN− < CO
Then NH3 makes the ΔOh higher and it requires a higher energy light to make the transition, which means a shorter wavelength.
Answer:
1s^2..2s^2..2p^6..3s^1
Explanation:
Since sodium has 11 electrons...its electron configuration is...;
1s^2..2s^2..2p^6..3s^1
;The powers of the energy levels(i.e s,p,d) should all add up to the number of electrons in an atom
*.When writing...please do not separate them.
Answer:
Explanation:
Molecular equation for the reaction:
HI(aq) + KOH(aq) --> KI(aq) + H2O(l)
Ionic equation
K+(aq) + OH-(aq) + H+(aq) + I-(aq) --> K+(aq) + I-(aq) + H2O(l)
Net ionic equation:
H+(aq) + OH-(aq) --> H2O(l)
The reaction equation:
2H₂O + 2Na₂O₂ → 4NaOH + O₂
Moles of sodium peroxide = 10 / 78 = 0.128
Moles of oxygen released = 0.128 / 2 = 0.064 mol
Mass of oxygen = 0.064 x 32
Mass of oxygen = 2.05 grams
