Answer:
Theoretical yield of sodium chloride = 14.04 g
Explanation:
Given data:
Mass of sodium bromide = 25 g
Theoretical yield of sodium chloride = ?
Solution:
Chemical equation:
NaBr + KCl → NaCl + KBr
Number of moles sodium bromide:
Number of moles = Mass /molar mass
Number of moles = 25.0 g / 102.9 g/mol
Number of moles = 0.24 mol
Now we will compare the moles of NaCl with NaBr .
NaBr : NaCl
1 : 1
0.24 : 0.24
Theoretical yield of sodium chloride:
Mass = moles × molar mass
Mass = 0.24 mol × 58.5 g/mol
Mass = 14.04 g
Answer:0.00000009
Explanation:
9.11 × （1/1000000000）=0.00000009
I cause the water to het up, when it do it become a gas.
Answer:
16.5 dm³
Explanation:
Data Given:
no. moles of O₂ = 0.735 moles
volume of O₂ = ?
Solution:
Now
we have to find volume of O₂ gas
Formula used for this purpose
No. of moles = Volume / molar volume
where
molar volume at STP for Oxygen (O₂) = 22.4 dm³/mol
No. of moles O₂ = Volume of O₂ / 22.4 dm³/mol . . . . . .(1)
Put values in equation 1
0.735 = Volume of O₂ / 22.4 dm³/ mol
rearrange above equation
Volume of O₂ = 0.735 x 22.4 dm³/ mol
Volume of O₂ = 16.5 dm³
So,
the volume of O₂ at STP is 16.5 dm³
