Please help, the problem is due tomorrow

over the summer steven"s tutor told him he needed to complete 15 total workbook pages. he finished 5 workbook pages the first we

Eduardwww [97]

He has 2/3 left to complete.
He did 5 out of 15 which is 5/15 or 1/3. Therefore he has 1-1/3 or 2/3 left.

7 0

3 years ago

Lines k and n intersect on the y-axis

avanturin [10]

a) The equation of line k is:

$y = -\frac{202}{167}x + \frac{598}{167}$

b) The equation of line j is:

$y = \frac{167}{202}x + \frac{1546}{202}$

The equation of a line, in <u>slope-intercept formula</u>, is given by:

$y = mx + b$

In which:

m is the slope, which is the rate of change.
b is the y-intercept, which is the value of y when x = 0.

Item a:

Line k intersects line m with an angle of 109º, thus:

$\tan{109^{\circ}} = \frac{m_2 - m_1}{1 + m_1m_2}$

In which $m_1$ and $m_2$ are the slopes of <u>k and m.</u>

Line k goes through points (-3,-1) and (5,2), thus, it's slope is:

$m_1 = \frac{2 - (-1)}{5 - (-3)} = \frac{3}{8}$

The tangent of 109 degrees is $\tan{109^{\circ}} = -\frac{29}{10}$
Thus, the slope of line m is found solving the following equation:

$\tan{109^{\circ}} = \frac{m_2 - m_1}{1 + m_1m_2}$

$-\frac{29}{10} = \frac{m_2 - \frac{3}{8}}{1 + \frac{3}{8}m_2}$

$m_2 - \frac{3}{8} = -\frac{29}{10} - \frac{87}{80}m_2$

$m_2 + \frac{87}{80}m_2 = -\frac{29}{10} + \frac{3}{8}$

$\frac{167m_2}{80} = \frac{-202}{80}$

$m_2 = -\frac{202}{167}$

Thus:

$y = -\frac{202}{167}x + b$

It goes through point (-2,6), that is, when $x = -2, y = 6$ , and this is used to find b.

$y = -\frac{202}{167}x + b$

$6 = -\frac{202}{167}(-2) + b$

$b = 6 - \frac{404}{167}$

$b = \frac{6(167)-404}{167}$

$b = \frac{598}{167}$

Thus. the equation of line k, in slope-intercept formula, is:

$y = -\frac{202}{167}x + \frac{598}{167}$

Item b:

Lines j and k intersect at an angle of 90º, thus they are perpendicular, which means that the multiplication of their slopes is -1.

Thus, the slope of line j is:

$-\frac{202}{167}m = -1$

$m = \frac{167}{202}$

Then

$y = \frac{167}{202}x + b$

Also goes through point (-2,6), thus:

$6 = \frac{167}{202}(-2) + b$

$b = \frac{(2)167 + 202(6)}{202}$

$b = \frac{1546}{202}$

The equation of line j is:

$y = \frac{167}{202}x + \frac{1546}{202}$

A similar problem is given at brainly.com/question/16302622

7 0

2 years ago

Given the data set (200,150,325,100,75) find the mean of the data set

Nina [5.8K]

To find the mean (average), u add up all the numbers, then divide by how many numbers there are.

(200 + 150 + 325 + 100 + 75) / 5 = 850/5 = 170 <== the mean

7 0

3 years ago

What is the average cost of cleaning if there were seperate costs of $1,614.23 $2,196.27, $1,560.58 and $1,392.52

cupoosta [38]

Add them up then divide them by 4.
6763.6/4 = 1690.9 average.

5 0

2 years ago

Read 2 more answers

Someone pls help me with this and I’ll mark you as brainliest!!

MrRissso [65]

Answer:

2. I am pretty sure that it is right angles are congruent.

4. Angle O and R are congruent, never heard of their angles theorem but I think it might be related to CPCTC.

Step-by-step explanation:

Well a square is always used to represent a right angle so and both angle Q and N have squares and that should mean that they are both 90 degrees. Also while vertical angels are congruent, angles Q and N are not vertical from each other, Reflexive Property is if it is a side and not an angle I think.

5 0

3 years ago