The answer is 3.03 g
Ar(H) = 1.01 g/mol
Since there are three atoms in Al(OH)3, the total atomic mass of hydrogen in Al(OH)3 is:
3 * Ar(H) = 3 * 1.01 g/mol = 3.03 g/mol
The mass (m) is atomic mass (Ar) divided by the number of moles n):
m = Ar/n
Ar = 3.03 g/mol
n = 1 mol
m = 3.03 g/mol / 1 mol = 3.03 g
___3% H2O2 (mass/vol)
<span>a) mass bought = 3g/100ml * 250 ml = ?? g H2O2 </span>
<span>b) moles / 0.250 liter = (?? g H2O2 / MW H2O2 g/mole) / 0.250 liter = ??M </span>
<span>Plug and SOLVE </span>
<span>Basic mathematics is a prerequisite to chemistry – I just try to help you with the methodology of solving the problem.
</span>
Hydrogen in heavy water is an isotope of Hydrogen (Deuterium)
so, it's different
Moles of glucose = Molarity x volume solution
= 4.5 x 1.5
= 6.75 moles.
Hope this helps, have a great day ahead!