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3 years ago

Which of the following best describe arrangement of particles in a gas?

Chemistry

1 answer:

Maslowich3 years ago

8 0

Answer:

last one

Explanation:

makes the most sense

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Fudgin [204]

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3 years ago

On a mission to a newly discovered planet, an astronaut finds gallium abundances of 61.29% for 69Ga and 39.71% for 71Ga. What is

Verizon [17]

(exact weight of isotope #1) (abundance of isotope #1) + (exact weight of isotope #2) (abundance of isotope #2) = average atomic weight of the element(68.72*61.29) + (39.71*70.92) = 4211.84 + 2816.237028.07/100= 70.28

70.28 is the atomic mass of Gallium for the location

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3 years ago

Methyl red is a common acid-base indicator. it has a ka equal to 6.3 × 10–6. its un-ionized form is red and its anionic form is

Maksim231197 [3]

Hello!

The pKa of an indicator tells us the pH where it changes color. The pKa of Methyl red is

$pKa=-log(Ka)=-log( 6,3*10^{-6} )=5,20$

So, at a pH=7,8, Methyl Red would be at a pH over its pKa, so it would be in its basic form. The Basic Form of Methyl Red is Yellow, so the solution would be Yellow.

Have a nice day!

7 0

3 years ago

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jarptica [38.1K]

What is the senerio? Is there a picture that goes along with it ??

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3 years ago

Read 2 more answers

A mixture of 0.10 mol of NO, 0.050 mol of H2, and 0.10 mol of H2O is placed in a 1.0- L vessel at 300 K . The following equilibr

umka2103 [35]

Answer:

The concentration of N2 at the equilibrium will be 0.019 M

Explanation:

Step 1: Data given

Number of moles of NO = 0.10 mol

Number of moles of H2 = 0.050 mol

Number of moles of H2O = 0.10 mol

Volume = 1.0 L

Temperature = 300K

At equilibrium [NO]=0.062M

Step 2: The balanced equation

2NO(g) + 2H2(g) → N2(g) + 2H2O(g)

Step 3: Calculate the initial concentration

Concentration = Moles / volume

[NO] = 0.10 mol / 1L = 0.10 M

[H2] = 0.050 mol / 1L = 0.050 M

[H2O] = 0.10 mol / 1L = 0.10 M

[N2] = 0 M

Step 4: Calculate the concentration at the equilibrium

[NO] at the equilibrium is 0.062 M

This means there reacted 0.038 mol (0.038M) of NO

For 2 moles NO we need 2 moles of H2 to produce 1 mol N2 and 2 moles of H2O

This means there will also react 0.038 mol of H2

The concentration at the equilibrium is 0.050 - 0.038 = 0.012 M

There will be porduced 0.038 moles of H2O, this means the final concentration pf H2O at the equilibrium is 0.100 + 0.038 = 0.138 M

There will be produced 0.038/2 = 0.019 moles of N2

The concentration of N2 at the equilibrium will be 0.019 M

5 0

4 years ago