If you answer this question I’ll give you 20 points

Mathematics

1 answer:

sukhopar [10]3 years ago

3 0

Answer:

2) $\frac{3(x-1)}{x^2}$

Step-by-step explanation:

$\frac{3x^2+12x-15}{x^3+5x^2} \\\\\frac{3(x-1)}{x^2}$

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For his birthday, Tyrone's parents gave him $7,790.00 which they put into a savings account that earns 15% interest compounded m

torisob [31]

Answer:

5 years and 5 months

Step-by-step explanation:

Compound Interest Formula

$\large \text{$ \sf A=P(1+\frac{r}{n})^{nt} $}$

where:

A = final amount
P = principal amount
r = interest rate (in decimal form)
n = number of times interest applied per time period
t = number of time periods elapsed

Given:

A = $17,474.00
P = $7,790.00
r = 15% = 0.15
n = 12
t = number of years

Substitute the given values into the formula and solve for t:

$\implies \sf 17474=7790\left(1+\dfrac{0.15}{12}\right)^{12t}$

$\implies \sf \dfrac{17474}{7790}=\left(1.0125}\right)^{12t}$

$\implies \sf \ln\left(\dfrac{17474}{7790}\right)=\ln \left(1.0125}\right)^{12t}$

$\implies \sf \ln\left(\dfrac{17474}{7790}\right)=12t \ln \left(1.0125}\right)$

$\implies \sf t=\dfrac{\ln\left(\frac{17474}{7790}\right)}{12 \ln \left(1.0125}\right)}$

$\implies \sf t=5.419413037...\:years$

Therefore, the money was in the account for 5 years and 5 months (to the nearest month).

3 0

2 years ago

Read 2 more answers

It took 3/4h to complete 1game of cards.How many games can be completed 2 1/4h?

Crank

I would prefer to solve this in a decimal form
I will show this to u in 2 ways
1:.75::X:2.25
(1*2.25)/.75x
2.25/.75x
X=3

2.25/.75=3
when we divide the number of hours played by hors for one game we get the number of games that could be played

7 0

3 years ago

The table shows how many males and females attended two different movies. How would you find the joint relative frequency of bei

kirza4 [7]

Answer:

B. Divide 124 by 229.

Step-by-step explanation:

Given the table

$\begin{array}{cccc}&\text{Action}&\text{Drama}&\text{Total}\\ \\\text{Male}&105&124&229\\ \\\text{Female}&99&151&250\\ \\\text{Total}&204&275&479\end{array}$